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maxonik [38]
3 years ago
5

What is the equation in standard form of a parabola that contains the following points

Mathematics
1 answer:
azamat3 years ago
5 0
Equation of a parabola is given by
y = ax^2 + bx + c
From the given points
-16 = a(-2)^2 + b(-2) + c = 4a - 2b + c . . . (1)
4 = a(0)^2 + b(0) + c = c . . . (2)
-28 = a(4)^2 + b(4) + c = 16a + 4b + c . . . (3)

Putting (2) into (1) and (2) gives:
4a - 2b + 4 = -16
4a - 2b = -20 . . . (4)
16a + 4b + 4 = -28
16a + 4b = -32 . . . (5)
(4) x 4 => 16a - 8b = -80 . . . (6)
(5) - (6) => 12b = 48
b = 48/12 = 4

From (4), 4a - 2(4) = -20
4a = -20 + 8 = -12
a = -12/4 = -3

Therefore, the required polynomial is
y = -3x^2 + 4x + 4
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Step-by-step explanation:

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A parallelogram is a special type of quadrilateral that has both pairs of opposite sides parallel and equal.

So from the given question the given figure can be inferred which is attached below

The "y" side of the parallelogram corresponds to the bigger side of the parallelogram, as seen in the figure, and the "x" side corresponds to the shorter side.

Since "y" relates to the longer side and the longer side is 15 cm, the 15 cm side is equivalent to the y centimeter side.

Learn more about parallelogram here :

brainly.com/question/19648711

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