For this case we have the following system of two equations with two unknowns:
We want to know if the point is the solution of the system:
We replace:
, meets the first equation.
does not comply with the second equation.
Therefore, it is not system solution.
Answer:
The point is not system solution
<span>perimeter = 2(a +b), where a = length and b = width
p = 68
a+b = 34
so
a = 34-b
.
diagonal = c = 26 cm
.
Pythagorean Theorem teaches us that:
.
c^2 = a^2 + b^2
.
Substitute for a = 34-b and c = 26
.
26^2 = (34-b)^2 + b^2
,
Collect terms.
.
676 = (b^2 -68b + 1156) + b^2
.
2b^2 -68b + 480 = 0
.
b^2 -34b +240 = 0</span>
Answer:
sample space { HH, HT ,TH ,TT}
Step-by-step explanation:
the possibilities are head and tails, H or T
so you can get heads heads, heads tails, tail heads or tail tails
4,248 times 0.90 equals 3823.2; so 3823.2 students are enrolled.