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makvit [3.9K]
4 years ago
12

Given the box plot, Which of the median and mean will best describe of the center?

Mathematics
1 answer:
Dmitry [639]4 years ago
7 0
<span>D is the correct answer. The data ranges from 11 to 37.5, but the median and Q3 are closer to the higher end. This means the data is skewed to the right, because the higher values are on the right of the axis.</span>
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This is Slope-Intercept Form! How do I write the slope intercept form for these Graphs???
bogdanovich [222]
Your question was already in slope intercept form. See picture for photo of the graph and mark me as brainliest if you think i helped :)

4 0
4 years ago
A bakery made 100 donuts, in the display case, 40/100 were chocolate, 3/10 were glazed and cinnamon. which fraction of the donut
Evgesh-ka [11]
57 of them were cinnamon.

Explanation:

100-40 = 60 and 3 of those were glazed so that leaves us with 57
7 0
3 years ago
Help
garik1379 [7]
What happened in the 1920s that greatly lowered the price of cars (automobiles) and other consumer products?
3 0
3 years ago
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Karl rides his bicycle 120 feet in 10 seconds. How many feet does he ride in 1 minute
Bumek [7]

A minute is 6 times as long as 10 seconds, so we expect Karl will ride 6 times as far.

\dfrac{120\,ft}{10\,s}=\dfrac{120\,ft}{10\,s}\cdot\dfrac{60\,s}{1\,min}=\dfrac{720\,ft}{1\,min}

Karl rides 720 ft in 1 minute.

7 0
3 years ago
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P.S ( The calculator given to me doesnt work ;-; ) NEED HELP ASAP FOR MY HOMEWORK ASSIGNMENT!! IF YOU ANSWER RIGHT ILL MARK YOU
wolverine [178]

Answer for the first box:  20

Answer for the second box: 6

====================================================

Explanation:

The notation a(1) represents the first term of the sequence given. The first term is 20, so thats why a(1) = 20.

The notation a(n) = a(n-1) + ____ means we add some term to the previous term to get the next. This process happens over and over. In this case, we add 6 to each term to get the next

  • term1 = 20
  • term2 = term1 + 6 = 20 + 6 = 26
  • term3 = term2 + 6 = 26 + 6 = 32
  • term4 = term3 + 6 = 32 + 6 = 38

and so on...

So we write a(n) = a(n-1) + 6

This value of 6 can be found by selecting any term and subtracting off the previous term, so we could say any of the following below

  • term2 - term1 = 26 - 20 = 6
  • term3 - term2 = 32 - 26 = 6
  • term4 - term3 = 38 - 26 = 6

That's how we end up with

\begin{cases}a(1) = 20\\a(n) = a(n-1) + 6\end{cases}

-------------------------

Extra info:

The common difference is d = 6 and the first term is a = 20

We can use these two facts to find the nth term a(n)

a(n) = a + d*(n-1)

a(n) = 20 + 6*(n-1)

a(n) = 20 + 6n - 6

a(n) = 6n + 14

Then note how plugging in n = 1 leads to

a(n) = 6*n + 14

a(1) = 6*1 + 14

a(1) = 20

and n = 2 leads to

a(n) = 6*n + 14

a(2) = 6*2 + 14

a(2) = 26

and so on

This allows us to plug in any value of n we want, without having to generate the previous terms before it. So for instance, you could plug in n = 100 to jump directly to the 100th term. If you use the recursive definition in the last section, then you have to generate the first 99 terms first before you can get to the 100th term.

7 0
3 years ago
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