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SVETLANKA909090 [29]
3 years ago
10

The similarity ratio of two regular octagons is 5:9. The area of the smaller octagon is 100 in2. Find the area of the larger oct

agon.
180 in2

349 in2

324 in2

165 in2
Mathematics
2 answers:
dlinn [17]3 years ago
7 0
<h3>Answer:</h3><h3>349 in2</h3><h3>Step_by _step explanation:</h3>

satela [25.4K]3 years ago
6 0

Answer:

180 in2

Step-by-step explanation:

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Please help i need it quickly i only have 5 minutes left. ill give brainliest.
Gemiola [76]

Answer:

A

B

C

Step-by-step explanation:

A

11=4(7)-17

11=28-17

11=11

B

-13=4(1)-17

-13=4-17

-13=-13

C

-1=4(4)-17

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6 0
3 years ago
Let f(x) = x^2 – 81. Find f–1(x). <br> Can someone double-check what I have?
Trava [24]
I hope this helps you



y=x^2-81


x^2=y+81


x=square root of y+81


f^-1 (x)= square root of x+81
5 0
3 years ago
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PLEASE HELP ASAP!!!!​
Elodia [21]

Answer:

I think its D? I'm not sure sorry if I get it wrong

7 0
2 years ago
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Can someone help me
Lady_Fox [76]

It is multiplying by 20. Therefor output for 10 would be 200.  the missing input would be 8 making the output 160

7 0
3 years ago
Suppose you are the manager of Speedy Oil Change which claims that it will change the oil in​ customers’ cars in less than 30 mi
Veronika [31]

Answer:

Explained below.

Step-by-step explanation:

(1)

The hypothesis can be defined as follows:

<em>H</em>₀: The Speedy Oil Change will change the oil in​ customers’ cars in more than 30 minutes on average, i.e. <em>μ</em> > 30.

<em>H</em>ₐ: The Speedy Oil Change will change the oil in​ customers’ cars in less than 30 minutes on average, i.e. <em>μ</em> ≤ 30.

(2)

Use Excel to compute the sample mean and standard deviation as follows:

\bar x=\text{AVERAGE(array)}=24.917\\\\s=\text{STDEV.S(array)}=8.683

Compute the test statistic as follows:

t=\frac{\bar x-\mu}{s/\sqrt{n}}=\frac{24.917-30}{8.683/\sqrt{36}}=-3.51

The degrees of freedom is:

df = n - 1

   = 36 - 1

   = 35

Compute the p-value as follows:

p-value=P(t_{35}

(3)

The <em>p</em>-value = 0.0006 is very small.

The null hypothesis will be rejected at any of the commonly used significance level.

(4)

There is sufficient evidence to support the claim that the Speedy Oil Change will change the oil in​ customers’ cars in less than 30 minutes on average.

3 0
3 years ago
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