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Firlakuza [10]
3 years ago
5

Titus is asked to prove hexagon FEDCBA is congruent to hexagon

Mathematics
2 answers:
Lyrx [107]3 years ago
7 0

Answer:

correct

Step-by-step explanation:

he is correct because the transformation is a translation and under the translation the image and preimage are congruent.

the measure of the sides are preserved, and the peasure of the angles are preserved so if all the corsponding sides and angles are congruent the hexagons are congruent too

Crank3 years ago
7 0

Answer:

<em>(x, y) -----> ( - x , y - 10 )</em>

Step-by-step explanation:

Titus is not correct.

There are two transformations will correctly prove FEDCBA ≅ F'E'D'C'B'A'

First transformation is Reflection over y-axis , then translation 10 units down.

The final formula is <em>( - x , y - 10 )</em>

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Given that a=43 ,b=82 , and c=28, solve triangle abc. round to the nearest tenth.
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Answer:

NO triangle exists.

Step-by-step explanation:

Given that the sides of the triangle are  a=43 ,b=82 , and c=28

To solve for unknown angles of the triangle

PLease refresh the triangle rule of inequality that the sum of any two sides is always greater than the third side

Before solving the triangle, let us check whether this is true.

a+b >c

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But a+c is not greater than b.

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3 years ago
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Use the vertical method to multiply (4a3 – 2a + 3a2 + 1) and (3 - 2a + a²).
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Answer:

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In how many ways can ann, bob, chuck, don and ed be seated in a row such that ann and bob are not seated next to each other?
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The 5 people can seat in a row in 5! ways
But we need to exclude the ways <span>that ann and bob are seated next to each other which is = 4! * 2!
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So, the number of <span>ways can ann, bob, chuck, don and ed be seated in a row such that ann and bob are not seated next to each other = 5! - 4! * 2! = 72
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<span>=====================================================
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<span>Another solution:
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<span>If ann seated in one of the ends, the number of ways = 3*2
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<span>If ann didn't seat in one of the ends , the number of ways = 2*3
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The remaining persons can seat with a number of ways = 3! = 6
So, the total ways that the five persons can seat = 12*6 = 72
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3 years ago
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