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Firlakuza [10]
3 years ago
5

Titus is asked to prove hexagon FEDCBA is congruent to hexagon

Mathematics
2 answers:
Lyrx [107]3 years ago
7 0

Answer:

correct

Step-by-step explanation:

he is correct because the transformation is a translation and under the translation the image and preimage are congruent.

the measure of the sides are preserved, and the peasure of the angles are preserved so if all the corsponding sides and angles are congruent the hexagons are congruent too

Crank3 years ago
7 0

Answer:

<em>(x, y) -----> ( - x , y - 10 )</em>

Step-by-step explanation:

Titus is not correct.

There are two transformations will correctly prove FEDCBA ≅ F'E'D'C'B'A'

First transformation is Reflection over y-axis , then translation 10 units down.

The final formula is <em>( - x , y - 10 )</em>

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Step-by-step explanation:

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\text{Hey there!}

\text{Distribute the value of 7 in each of your terms}

\text{(2x}^3+\text{3y}^2)(7)

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\boxed{\boxed{\bf{Answer:14x^3+21y^2}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

8 0
3 years ago
Read 2 more answers
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