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2 years ago

Plz help thank you no mean comment lovesomethingsomething(I don’t care enough to write her whole name)thank you

Mathematics

1 answer:

Alex_Xolod [135]2 years ago

3 0

The answer is 144 because you have to do this 4 ×(2+34).it is telling you that the x equals to 4 that’s why it is 34 not 3x.

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The product of w and 2 is greater than or equal to 19.

madam [21]

Equation Form:

w x 2 $\geq$ 19

Divide both sides by 2:

w $\geq$ 9.5

So, w must be equal to or greater than 9.5 for this equation to work.

5 0

2 years ago

Marina has $145 to spend. She spends $68. 50 on jeans. T-shirts cost $12. 75. Write and solve an inequality to find the greatest

Kruka [31]

Answer:

Step-by-step explanation:

145-68.50 = 76.50

76.20/12.75 = no of t-shirts she can buy

ans= 6

6 0

2 years ago

Mary spent a total of $352.24 for a party. She spent $200.29 on food, plus an additional $30.39 for each hour of the party. How

FinnZ [79.3K]

The answer should be 5 hours.

8 0

3 years ago

Read 2 more answers

Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu

Alisiya [41]

Let $y=C_1x+C_2x^3=C_1y_1+C_2y_2$ . Then $y_1$ and $y_2$ are two fundamental, linearly independent solution that satisfy

$f(x,y_1,{y_1}',{y_1}'')=0$
$f(x,y_2,{y_2}',{y_2}'')=0$

Note that ${y_1}'=1$ , so that $x{y_1}'-y_1=0$ . Adding $y''$ doesn't change this, since ${y_1}''=0$ .

So if we suppose

$f(x,y,y',y'')=y''+xy'-y=0$

then substituting $y=y_2$ would give

$6x+x(3x^2)-x^3=6x+2x^3\neq0$

To make sure everything cancels out, multiply the second degree term by $-\dfrac{x^2}3$ , so that

$f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y$

Then if $y=y_1+y_2$ , we get

$-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0$

as desired. So one possible ODE would be

$-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0$

(See "Euler-Cauchy equation" for more info)

6 0

3 years ago

39/360 in simplest form

Sergeeva-Olga [200]

Answer:

$= \frac{13}{120}$

5 0

2 years ago