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kolbaska11 [484]
3 years ago
12

given the parallel lines cut by. a transversal , determine the value of x . please help due in 30 minutes

Mathematics
2 answers:
Mademuasel [1]3 years ago
7 0

Answer:

x = 20

Step-by-step explanation:

The angles are same side interior angles so the add to 180

3x-10 + 5x+30 = 180

Combine like terms

8x +20 =180

Subtract 20 from each side

8x+20 -20 =180-20

8x = 160

Divide by 8

8x/8 =160/8

x = 20

Tresset [83]3 years ago
3 0

Answer: x = 25

Step-by-step explanation:

When lines are parallel, the same side interior angles are supplementary, meaning they add up to 180 degrees. So to find x, you would add the two expressions and make it equal to 180 degrees.

3x - 10 + 5x + 30 = 180

8x - 20 = 180

8x = 200

x = 25

The answer is x=25

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\displaystyle\\&#10;P(x)=3x^3-5x^2-14x-4\\\\&#10;D_{-4}=\{-4;~-2;~\underline{\bf -1};~1;~2;~4\}\\\\&#10;\text{We observe that } \frac{-1}{3} \text{ is a solution of the equation:}\\&#10;3x^3-5x^2-14x-4=0\\\\&#10;

\displaystyle\\&#10;\text{Verification}\\\\&#10;3x^3-5x^2-14x-4=\\\\&#10;=3\times\Big(-\frac{1}{3}\Big)^3-5\times\Big(-\frac{1}{3}\Big)^2-14\times\Big(-\frac{1}{3}\Big)-4=\\\\&#10;=-\frac{1}{9}-\frac{5}{9}+\frac{14}{3}-4=\\\\&#10;=-\frac{6}{9}+\frac{14}{3}-4=\\\\&#10;=-\frac{6}{9}+\frac{42}{9}- \frac{4\times 9}{9}=\\\\&#10; =-\frac{6}{9}+\frac{42}{9}- \frac{36}{9}= \frac{42-6-36}{9}=\frac{42-42}{9}=\frac{0}{9}=0\\\\&#10;\Longrightarrow~~~P(x)~\vdots~\Big(x+ \frac{1}{3}\Big)\\\\&#10;\Longrightarrow~~~P(x)~\vdots~(3x+1)


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