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VLD [36.1K]
3 years ago
6

99 POINTS FOR WHOEVER CAN ANSWER THESE! Please show work!

Mathematics
2 answers:
larisa [96]3 years ago
3 0
1. The slope is the y-difference divided by the x-difference:
.. m = (5 -5)/(4 -(-3)) = 0
The slope of the line is 0.

2. In point-slope form, the equation is
.. y = -2(x -2) +3
Expanding to slope-intercept form, you have
.. y = -2x +7

3. You can start with point-slope form
.. y = 5(x -0) +2
.. 5x -y = -2 . . . . . standard form

4) The questions seem to relate to a parabola. The given equation is a linear equation. Perhaps you mean
.. y = -3x² +5x +7
a) the negative coefficient of x^2 tells you the graph opens downward.

b) The vertex x-coordinate is -5/(2*(-3)) = 5/6. The y-value of the vertex is
.. (-3*5/6 +5)*5/6 +7 = 5/2*5/6 +7 = 9 1/12
As an ordered pair, the vertex is (x, y) = (5/6, 9 1/12)

koban [17]3 years ago
3 0
1) What is the slope of the line through the points (–3, 5) and (4, 5)?
P1=(-3,5)=(x1,y1)→x1=-3, y1=5
P2=(4,5)=(x2,y2)→x2=4, y2=5
Slope: m=(y2-y1) / (x2-x1)
m=(5-5) / (4-(-3))
m= (0) / (4+3)
m= (0) / (7)
m=0
Answer: The slope of the line through the points (-3,5) and (4,5) is 0.

2) Write an equation in slope-intercept form that represents a line with slope -2 through the point (2, 3).
Slope: m=-2
Point P1=(2,3)=(x1,y1)→x1=2, y1=3
y-y1=m(x-x1)
y-3=-2(x-2)
y-3=-2x+4
y-3+3=-2x+4+3
y=-2x+7
Answer: Equation in slope-intercept form that represents a line with slope -2 through the point (2,3) is y=-2x+7

3) Write an equation in standard form that represents a line with slope 5 through the point (0, 2).
Slope: m=5
Point P1=(0,2)=(x1,y1)→x1=0, y1=2
y-y1=m(x-x1)
y-2=5(x-0)
y-2=5x
y-2-y=5x-y
-2=5x-y
5x-y=-2
Answer: The equation in standard form that represents a line with slope 5 through the point (0, 2) is 5x-y=-2

4) Answer the following questions for the equation: y = -3x^2+5x+7 What direction does the graph open? State the vertex as an ordered pair.
y=ax^2+bx+c
a=-3, b=5, c=7
a=-3<0, then the graph opens downward
Vertex: V=(xv,yv)=(h,k)
xv=h=-b/(2a)
h=-5 / [2(-3)]
h= -5 / (-6)
h=5/6

yv=k=-3(5/6)^2+5(5/6)+7
k=-3 [ (5)^2 / (6)^2 ]+(5*5)/6+7
k=-3(25/36)+25/6+7
k=-25/12+25/6+7
k=(-25+2*25+12*7) / 12
k=(-25+50+84) / 12
k=109/12
Vertex: V=(5/6,109/12)
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Compute the value of the discriminant and give the number of real solutions of the quadratic equation.
Sergio039 [100]
-2x^2+6x-3=0 \\ \\&#10;a=-2 \\ b=6 \\ c=-3 \\ \Delta=b^2-4ac=6^2-4 \times (-2) \times (-3)=36-24=12

The value of the discriminant is 12.
Since the discriminant is greater than zero, the equation has two real solutions.
4 0
3 years ago
help pls The circumference of the hub cap of a tire is 80.1 centimeters. Find the area of this hub cap. Use 3.14 for pi. Use pen
Liula [17]

Answer: The area is 510.25 cm². If the circumference of the cap were smaller then the area would be smaller as well

Step-by-step explanation:

First, you must find the radius

<em>80.1 ÷ 3.14 = 25.5</em>

<em>25.5 ÷ 2 = 12.75 <---- radius</em>

Then from that, you find the area

A=πr²

<em>12.75² = 162.5</em>

<em>162.5 × 3.24 = 510.25</em>

<em></em>

<em>Hope this was helpful!</em>

<em></em>

3 0
2 years ago
Read 2 more answers
Please help im stuck .-_-.
fredd [130]

Answer:

y = 4

Step-by-step explanation:

y/16 = 5/20 = 2/8

y/16 = 1/4 = 1/4

4 0
2 years ago
Read 2 more answers
Write the next three terms of the geometric sequence.
mihalych1998 [28]

I think you posted this question more than once..

8 0
3 years ago
The population of Luis’s city in 2005 was 7400 and the population in 2010 was 9000. Let x represent the number of years since 20
podryga [215]

Answer:

The linear equation is;

y = 320x + 7400

Step-by-step explanation:

Here, we want to write a linear equation that represents the population y at a year since 2005

To write this, we need points

Initially, we have (0,7400)

Since the difference between 2005 and 2010 is 5, the second point will be (5,9000)

Mathematically, we can get the slope as follows;

m = (y2-y1)/(x2-x1) = (9000-7400)/(5-0) = 1,600/5 = 320

The equation of the line can be represented using the general form as;

y = mx + b

where m is 320 and b is unknown

So we have the equation as;

y = 320x + b

we need to get b

To get b, we can use any point

let us use the point (0,7400)

substituting this;

7400 = 320(0) + c

c = 7400

so the equation is;

y = 320x + 7400

4 0
3 years ago
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