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VLD [36.1K]
3 years ago
6

99 POINTS FOR WHOEVER CAN ANSWER THESE! Please show work!

Mathematics
2 answers:
larisa [96]3 years ago
3 0
1. The slope is the y-difference divided by the x-difference:
.. m = (5 -5)/(4 -(-3)) = 0
The slope of the line is 0.

2. In point-slope form, the equation is
.. y = -2(x -2) +3
Expanding to slope-intercept form, you have
.. y = -2x +7

3. You can start with point-slope form
.. y = 5(x -0) +2
.. 5x -y = -2 . . . . . standard form

4) The questions seem to relate to a parabola. The given equation is a linear equation. Perhaps you mean
.. y = -3x² +5x +7
a) the negative coefficient of x^2 tells you the graph opens downward.

b) The vertex x-coordinate is -5/(2*(-3)) = 5/6. The y-value of the vertex is
.. (-3*5/6 +5)*5/6 +7 = 5/2*5/6 +7 = 9 1/12
As an ordered pair, the vertex is (x, y) = (5/6, 9 1/12)

koban [17]3 years ago
3 0
1) What is the slope of the line through the points (–3, 5) and (4, 5)?
P1=(-3,5)=(x1,y1)→x1=-3, y1=5
P2=(4,5)=(x2,y2)→x2=4, y2=5
Slope: m=(y2-y1) / (x2-x1)
m=(5-5) / (4-(-3))
m= (0) / (4+3)
m= (0) / (7)
m=0
Answer: The slope of the line through the points (-3,5) and (4,5) is 0.

2) Write an equation in slope-intercept form that represents a line with slope -2 through the point (2, 3).
Slope: m=-2
Point P1=(2,3)=(x1,y1)→x1=2, y1=3
y-y1=m(x-x1)
y-3=-2(x-2)
y-3=-2x+4
y-3+3=-2x+4+3
y=-2x+7
Answer: Equation in slope-intercept form that represents a line with slope -2 through the point (2,3) is y=-2x+7

3) Write an equation in standard form that represents a line with slope 5 through the point (0, 2).
Slope: m=5
Point P1=(0,2)=(x1,y1)→x1=0, y1=2
y-y1=m(x-x1)
y-2=5(x-0)
y-2=5x
y-2-y=5x-y
-2=5x-y
5x-y=-2
Answer: The equation in standard form that represents a line with slope 5 through the point (0, 2) is 5x-y=-2

4) Answer the following questions for the equation: y = -3x^2+5x+7 What direction does the graph open? State the vertex as an ordered pair.
y=ax^2+bx+c
a=-3, b=5, c=7
a=-3<0, then the graph opens downward
Vertex: V=(xv,yv)=(h,k)
xv=h=-b/(2a)
h=-5 / [2(-3)]
h= -5 / (-6)
h=5/6

yv=k=-3(5/6)^2+5(5/6)+7
k=-3 [ (5)^2 / (6)^2 ]+(5*5)/6+7
k=-3(25/36)+25/6+7
k=-25/12+25/6+7
k=(-25+2*25+12*7) / 12
k=(-25+50+84) / 12
k=109/12
Vertex: V=(5/6,109/12)
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Two non vertical lines have slopes m₁ and m₂ ​, respectively. The lines are parallel if "m₁ = m₂" and the "y-intercepts" are unequal; the lines are perpendicular if m₁ = 1/m₂.

<h3>What is slope of a line?</h3>

The slope of a line is a measurement of its steepness and direction.

The slope of a line formula computes the "vertical change" to "horizontal change" ratio between two distinct points along a line.

Some key features regarding the slopes of the lines are-

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A set of parallel lines always has the same inclination angle. Assume we possess two parallel lines l1 and l2 in the reference plane, inclined at angles θ1  and θ2 with the x-axis, respectively, such that the, θ2 = θ1.

m1 = m2

Therefore, the slopes of the two given parallel lines are equal.

2. Slope of Perpendicular Lines:

A pair of perpendicular lines everytime form a 90 angle. Imagine we have two perpendicular lines l2 and l1 in the coordinate plane, inclined at angles θ1 and θ2 with the x-axis, respectively, so that the provided angles follow the external angle theorem, θ2 =  θ1 + 90.

m1 = tan θ1

m2 = tan (θ1 + 90º) = - cot θ1

m1 × m2 = -1

Therefore, the product of slopes of two given perpendicular lines is equal to -1.

To know more about the slopes, here

brainly.com/question/16949303

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