A student can take three subjects in 40 ways.
<u>SOLUTION:</u>
Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.
A student must take one of each, how many different ways can this be done?
Now, number ways to take math course = 4
Number of ways to take science course = 5
Number of ways to take history course = 2
So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.
Hence, a student can take three subjects in 40 ways.
Step-by-step explanation:
the side on the left of 155 is 180-155 which is 25
the one on top of 120 is 180-120 which is 60 so the one on the right of x is 180-(25+60) which is 95
now the value of x is 180-95 which is 85.
in the second one x=180-100 because the angle on the bottom of x is corresponding to the one that's equal to 100, so x=180-100 which is 80
for the first one x=85
the second one x=80
Step-by-step explanation:
Your answer is y=15 for your problem
