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katrin [286]
3 years ago
14

Grade Salary GS-1 $1,461 GS-2 $1,591 GS-3 $1,793 GS-4 $2,013 GS-5 $2,252 The table shows the monthly salaries for different grad

es of U.S. government employees. Find the range of the data set a. $1,822 c. $661 b. $552 d. $791
Mathematics
1 answer:
lawyer [7]3 years ago
6 0

The range is the difference between the highest and lowest pays.

Highest pay: GS-5 - 2,252

Lowest pay: GS-1 - 1,461

Range = 2252 - 1461 = 791

The answer is D. $791

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Suppose a simple random sample of size 50 is selected from a population with σ=10σ=10. Find the value of the standard error of t
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Answer:

a) \sigma_{\bar x} = 1.414

b) \sigma_{\bar x} = 1.414

c) \sigma_{\bar x} = 1.414

d) \sigma _{\bar x} = 1.343

Step-by-step explanation:

Given that:

The random sample is of size 50 i.e the population standard deviation  =10

Size of the sample n = 50

a) The population size is infinite;

The standard error is determined as:

\sigma_{\bar x} = \dfrac{\sigma}{\sqrt{n}}

\sigma_{\bar x} = \dfrac{10}{\sqrt{50}}

\sigma_{\bar x} = 1.414

b) When the population size N= 50000

n/N = 50/50000 = 0.001 < 0.05

Thus ; the finite population of the standard error is not applicable in this scenario;

Therefore;

The standard error is determined as:

\sigma_{\bar x} = \dfrac{\sigma}{\sqrt{n}}

\sigma_{\bar x} = \dfrac{10}{\sqrt{50}}

\sigma_{\bar x} = 1.414

c)  When the population size N= 5000

n/N = 50/5000 = 0.01 < 0.05

Thus ; the finite population of the standard error is not applicable in this scenario;

Therefore;

The standard error is determined as:

\sigma_{\bar x} = \dfrac{\sigma}{\sqrt{n}}

\sigma_{\bar x} = \dfrac{10}{\sqrt{50}}

\sigma_{\bar x} = 1.414

d) When the population size N= 500

n/N = 50/500 = 0.1 > 0.05

So; the finite population of the standard error is applicable in this scenario;

Therefore;

The standard error is determined as:

\sigma _{\bar x} = \sqrt{\dfrac{N-n}{N-1} }\dfrac{\sigma}{\sqrt{n} } }

\sigma _{\bar x} = \sqrt{\dfrac{500-50}{500-1} }\dfrac{10}{\sqrt{50} } }

\sigma _{\bar x} = 1.343

7 0
3 years ago
• Since January 1980, the population, P, of the city of Brownville has increased closely modeling the
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Answer:

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A) 720,500 represents the initial amount of people in January 1980 and 1.022 represents the increase factor that multiplies to the amount.

Step-by-step explanation:

1.022 times 100 equals 102.2% (a number in the decimals place times 100 give you the percent).

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3 years ago
A tile installer plots an irregular shape on grid paper. Each square on the grid represents 1 square centimeter. What is the are
Gelneren [198K]

Answer:

34cm²

Step-by-step explanation:

Find diagram in the attached file.

Since each square on the grid represent 1cm², the length of the each square will be 1cm

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Area of the irregular shape = area of triangle + area of rectangle + area of parallelogram

For TRIANGLE

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Since the base of triangle is on 4square grid,

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Height = 2cm

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Area of ∆ = 4cm²

FOR RECTANGLE

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= 15cm²

FOR PARALLELOGRAM

Area of a parallelogram = Base × Height

Base = 5cm

Height = 3cm

Area = 5cm×3cm

Area = 15cm²

Area of the irregular shape = 4cm²+15cm²+15cm²

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Is 1/8 and 4/32 a proportion?
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Yes since 1/8 is equal to 4/32
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