If your PCR product size was 172 and there were 130 base pairs next to a 14 base pair repeat, then there are 3 repeats.
Given that the newly used primer amplifies 130 base pairs that are near
(a) 14 base pair and
(b) the size of the pcr product is 172
Size = (number of base pairs * number of repetitions) + Initial/Primer Amplicon Value
172 = (14 * x) + 130
172 -130 = 14x
42 = 14x
3 = x
Therefore, we can say that the PCR product has 3 repeats.
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Answer:
![4ft *\frac{12in}{1 ft}= 48 in](https://tex.z-dn.net/?f=%204ft%20%2A%5Cfrac%7B12in%7D%7B1%20ft%7D%3D%2048%20in)
Now since we have the same units for the scale model and the real one we can find the scale factor like this:
![Scale = \frac{48 in}{6in}= 8](https://tex.z-dn.net/?f=%20Scale%20%3D%20%5Cfrac%7B48%20in%7D%7B6in%7D%3D%208)
And we can conclude that the scale factor is 1:8 and that represent that the real object is 8 times larger than the scale model
Step-by-step explanation:
For this problem we know that the scale model had a widthof 6 inches. And the actual model has a width of 4ft. First we need to convert the 4ft to inches and we got:
![4ft *\frac{12in}{1 ft}= 48 in](https://tex.z-dn.net/?f=%204ft%20%2A%5Cfrac%7B12in%7D%7B1%20ft%7D%3D%2048%20in)
Now since we have the same units for the scale model and the real one we can find the scale factor like this:
![Scale = \frac{48 in}{6in}= 8](https://tex.z-dn.net/?f=%20Scale%20%3D%20%5Cfrac%7B48%20in%7D%7B6in%7D%3D%208)
And we can conclude that the scale factor is 1:8 and that represent that the real object is 8 times larger than the scale model
The nearest value of the mass is <span>3.27 grams
it s near 3.25
answer is c</span>
Answer:
2
Step-by-step explanation:
first write out the expression
(2 ^ 2)×(2^3)/(2^4)
using bodmas we deal with the division sign first as well as using the laws of indices. Thus we have
(2^2)×(2^[3-4])
= (2^2)×(2^-1)
=(2^[2+(-1)])
= (2^(2-1))
= (2^1)
= 2
Answer:
They purchased 11 Packets
Step-by-step explanation:
C=11p + 30