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3 years ago

11

Chelsea has 11 times as many art brushes as Monique. If they have 60 art brushes altogether, how many brushes does chelsea have

1 answer:

Keith_Richards [23]3 years ago

6 0

I did it on the calculator the answer was 0.1833333333333333 i do not know if this is correct if its incorrect then srry :(

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Use the stem and leaf plot graph to answer the question.

kogti [31]

<h3>Answer: 13 days</h3>

====================================================

Explanation:

Count the number of leaves marked in green.

Row One: 2 leaves (1 and 8)
Row Two: 3 leaves (3, 6, and 9)
Row Three: 5 leaves (2, 3, 4, 6, 7)
Row Four: 3 leaves (1, 6, and 8)

There are 2+3+5+3 = 13 leaves total. This represents tickets were sold on 13 days.

Each stem and leaf combines to form a different ticket count. For instance, the stem of 1 and leaf of 8 combine to get the value 18. So 18 tickets were sold on that particular day.

7 0

1 year ago

Use the formula for volume = ℎ to find the<br> volume of the rectangular prism shown.

Sedaia [141]

Answer: 56 / 729

Step-by-step explanation: (4 * 2 * 7) / (9^3)

3 0

2 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

2 years ago

Which relation is a function?

aksik [14]

Answer:

B

Step-by-step explanation:

5 0

2 years ago

Please help with this

xenn [34]

Answer:

Step-by-step explanation:

a

5 0

2 years ago

Read 2 more answers