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kolbaska11 [484]
2 years ago
6

Name a pair of complementary angles and a pair of supplementary angles

Mathematics
1 answer:
makkiz [27]2 years ago
5 0

Answer:

Step-by-step explanation:

m<POQ + m<SOR = 90º. This makes these two angles complementary.

m<POQ + m<QOR + m<SOR = 180º. This is because the measure of a straight line is 180º.

hope this helps, reach out if you have more questions!

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FHG is congruent EFH
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A line has the equation 3x ? 4y = 1. Choose the equation of a line that is parallel to the given line.
cupoosta [38]

Answer:

Find a line which also has 3/4 as the slope or 3x - 4y in standard form.

Step-by-step explanation:

If the line is 3x - 4y = 1 then the line which is parallel will have the same coefficients of x and y. Parallel lines never cross and to ensure this have the same slope. The slope is a ratio which can be solved for in an equation using the coefficients of x and y. Here the slope is:

3x - 4y = 1

-4y = -3x + 1

y = 3/4x - 1/4.

Find a line which also has 3/4 as the slope or 3x - 4y in standard form.

7 0
2 years ago
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telo118 [61]

Answer: -8

Step-by-step explanation:

3 - (-8) = 3+8

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6 0
2 years ago
What's the explicit formula for 5,10,15,20,25,30
vivado [14]

Answer:

a_{n} = 5n

Step-by-step explanation:

There is a common difference d between consecutive terms

d = 10 - 5 = 15 - 10 = 20 - 15 = 25 - 20 = 30 - 25 = 5

This indicates the sequence is arithmetic with explicit formula

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 5 and d = 5 , then

a_{n} = 5 + 5(n - 1) = 5 + 5n - 5 = 5n

4 0
2 years ago
given that sin theta= 1/4, 0 is less than theta but less than pi/2, what is the exact value of cos theta
lapo4ka [179]

Answer:

\cos{\theta} = \frac{\sqrt{15}}{4}

Step-by-step explanation:

For any angle \theta, we have that:

(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1

Quadrant:

0 \leq \theta \leq \frac{\pi}{2} means that \theta is in the first quadrant. This means that both the sine and the cosine have positive values.

Find the cosine:

(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1

(\frac{1}{4})^{2} + (\cos{\theta})^{2} = 1

\frac{1}{16} + (\cos{\theta})^{2} = 1

(\cos{\theta})^{2} = 1 - \frac{1}{16}

(\cos{\theta})^{2} = \frac{16-1}{16}

(\cos{\theta})^{2} = \frac{15}{16}

\cos{\theta} = \pm \sqrt{\frac{15}{16}}

Since the angle is in the first quadrant, the cosine is positive.

\cos{\theta} = \frac{\sqrt{15}}{4}

3 0
3 years ago
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