What is the area of the regular polygon?
1 answer:
Answer:
You could use the polygon area formula OR here's an easier solution
We draw the lines DC and DE
Angle ADC = 120°
Triangle ADC is a 30 60 90 triangle
In such a triangle Line AE = hypotenuse * sq root (3) /2
Line AE = 3 * 0.8660254038 = 2.5980762114
Line DE = 1.5
Area of Triangle ADE = .5 * 1.5 * 2.5980762114 =
1.9485571586 square meters and entire area of Triangle
ABC = 6 * 1.9485571586
which equals 11.6913429513 square meters
Step-by-step explanation:
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Answer:
C
Step-by-step explanation:
Given
2x² + x - 1 = 2 ( subtract 2 from both sides )
2x² + x - 3 = 0
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 2 × - 3 = - 6 and sum = + 1
The factors are - 2 and + 3
Use these factors to split the x- term
2x² - 2x + 3x - 3 = 0 ( factor the first/second and third/fourth terms )
2x(x - 1) + 3(x - 1) = 0 ← factor out (x - 1) from each term
(x - 1)(2x + 3) = 0
Equate each factor to zero and solve for x
x - 1 = 0 ⇒ x = 1
2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = -
The distance between points A (3, -5) and A' (2, -3) is 2.4 units.
Given that,
The points A (3, -5) and A' (2, -3).
We have to determine,
The distance between point A and A'.
According to the question,
The distance between two points is determined by using the distance formula.
Then,
The distance between points A (3, -5) and A' (2, -3) is,
Hence, The distance between points A (3, -5) and A' (2, -3) is 2.4 units.
For more details refer to the link given below.