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babymother [125]
3 years ago
14

In 1980 and again in 2010, a Gallup poll asked a random sample of 1000 US citizens people "Are you in favor of the death penalty

for a person convicted of murder?". In 1980, the proportion saying yes was 0.66. In 2010, it was 0.64. Does this data provide evidence that the proportion of US citizens favoring the death penalty was higher in 1980 than it was in 2010? State the null and alternative hypotheses: What is the sample statistic?
Mathematics
1 answer:
Digiron [165]3 years ago
7 0

Answer:

H0: p(1980) = p(2010) ; H1 : P(1980) > P(2010)

0.02

Step-by-step explanation:

Given that:

Sample size in both 1980 and 2010 = 1000 samples :

Proportion in favor :

P(1980) = 0.66

P(2010) = 0.64

To test the hypothesis :

Null hypothesis :

Proportion in favor are the same in both years

Null hypothesis = H0 = p(1980) = p(2010)

Alternative hypothesis :

Proportion in favor in 1980 is greater than that in 2010

Alternative hypothesis = H1 : P(1980) > P(2010)

The sample statistic :

P(1980) - p(2010)

0.66 - 0.64

= 0.02

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Answer:

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Step-by-step explanation:

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Hello!

So you figure that 7/10-5/10=2/10 that leave you with 1/5 left over. So if you take that into effect, all you have to do it multiply those 3 gallons by 5. Which gives you 15. So, your answer would be 15 gallons. 

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SuperHelperThingy
7 0
4 years ago
The half-life of uranium-238 is 4.5x10^9 years. The half-life of uranium-234 is 2.5x10^5 years. How many times greater is the ha
lara31 [8.8K]

<u>Answer:</u>

Half-life of uranium-238 18 \times 10^{3} \text { times greater } that of uranium-234

<u>Explanation:</u>

Half time of uranium-238 = 4.5\times 10^9  years

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To find how much times greater the half life of uranium-238 is from uranium-234

= \frac{\text { Half life of Uranium-238 }}{\text { Half time of Uranium - 234 }}

=\frac{4.5 \times 10^{9}}{2.5 \times 10^{5}}

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Hence Uranium-238 is  18 \times 10^{3} \text { times greater } than Uranium-234

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