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Rasek [7]
3 years ago
13

PLEASE JUST GIVE ME THE ANSWERS TO THE LAST TWO QUESTIONS

Mathematics
1 answer:
professor190 [17]3 years ago
8 0
Super easy just add 2 in front of Na H CO3(s). Your formula will be balanced.
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The points (-1, r) and (5, -5) lie on a line with slope - 3. Find the missing coordinate r.
stealth61 [152]
( 1, 2 ###############
6 0
3 years ago
Karita had $138.72 in her checking account. She wrote checks for $45.23 and $18.00. Then she made a deposit of $75.85 into her a
denis-greek [22]
138.72 - 45.23 - 18
These are the check costs that subtracted from her bank account
75.49 is what you get
A deposit is when you add money to your account, so, you add 75.85
75.49 + 75.85 = $151.34
3 0
3 years ago
Read 2 more answers
Which of the point-slope equations below are correct for the line that passes through points (-2, -2) and (2, 1)?
Ne4ueva [31]
Find slope first:
m =y2-y1/x2-x1
m = 1--2/2--2
m = 3/4

Select a point, insert your slope, & put it into point slope form:
y-y1 =m(x-x1)

Your final answers are:

y-1=3/4(x-2)
OR
y+2 =3/4(x+2)
8 0
3 years ago
Find an equation of the sphere with center (2, −10, 3) and radius 5. $$25=(x−2)2+(y−(−10))2+(z−3)2 use an equation to describe i
lana66690 [7]

In the x,y plane, we have z=0 everywhere. So in the equation of the sphere, we have

25=(x-2)^2+(y+10)^2+(-3)^2\implies(x-2)^2+(y+10)^2=16=4^2

which is a circle centered at (2, -10, 0) of radius 4.

In the x,z plane, we have y=0, which gives

25=(x-2)^2+10^2+(z-3)^2\implies(x-2)^2+(z-3)^2=-75

But any squared real quantity is positive, so there is no intersection between the sphere and this plane.

In the y,z plane, x=0, so

25=(-2)^2+(y+10)^2+(z-3)^2\implies(y+10)^2+(z-3)^2=21=(\sqrt{21})^2

which is a circle centered at (0, -10, 3) of radius \sqrt{21}.

3 0
3 years ago
After a reflection over the line x-axis, (8,11) is the image of point C. What is the original location of point C.
goblinko [34]
(-8, -11) because the points are just the opposite sign when reflecting over the x-axis
7 0
3 years ago
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