3 years ago

Factor the polynomial by grouping : x^3+5x^2-6x-30

Mathematics

1 answer:

andrew-mc [135]3 years ago

4 0

The idea is to pair up the terms, factor each sub-group, and then pull out the overall GCF to fully factor.

x^3+5x^2-6x-30

(x^3+5x^2)+(-6x-30)

x^2(x+5)+(-6x-30)

x^2(x+5)-6(x+5)

(x^2-6)(x+5)

-------------

Answer: (x^2-6)(x+5)

You might be interested in

Find the estimate & difference for 4-1.29

rewona [7]

Difference is 2.71 and the estimate is 3

4 0

3 years ago

Read 2 more answers

How do you distrubite this (x+5)(x+9)

ohaa [14]

Step-by-step explanation:

=x²+9x+5x+45

=x²+14x+45

Hope it helps 

7 0

2 years ago

6(+(14÷2-7))-8 order of operations

kakasveta [241]

How to get answer by Mimiwhatsup:

$Follow\:the\:PEMDAS\:order\:of\:operations\\\mathrm{Calculate\:within\:parentheses}\:\left(\left(14\div \:2-7\right)\right)\::\quad 0\\=6\cdot \:0-8\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:6\cdot \:0\::\quad 0\\=0-8\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:0-8\::\quad -8\\=-8$