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MakcuM [25]
3 years ago
11

Which of the following statements is false regarding randomization?

Mathematics
2 answers:
swat323 years ago
4 0

which are the statements, dude we can see the options,

Goshia [24]3 years ago
3 0

Answer:

Answer on Plato is Randomization can be replaced by accurately matching the sample to the population. You should never replace Randomization, you need it.

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I need help asap!!!
gizmo_the_mogwai [7]

Answer:

x = 9

Step-by-step explanation:

-5(1 + 1x) = -50

-5 + -5x = -50

-5 + -5x + 5 = -5x

-50 + 5 = -45

-5x = -45

-5x / -5 = x

-45 / -5 = 9

x = 9

5 0
3 years ago
Convert 32505 into equivalent number with base 5​
velikii [3]

1s -0

5s- 1

25s- 0

125s- 0

625s- 2

3125s- 0

15625s- 2

2020010. I think this is right but would like so confirmation, just taught myself this!

6 0
3 years ago
When solving 5 (<br>25) - 7. What is the correct sequence of operations? (5 points)​
Nana76 [90]

You would multiply 5 by 25 (125) and then subtract 7 (118). Parentheses, exponents, multiply/divide, then add/subtract.

3 0
3 years ago
What type of association does the graph show between x and y? A graph shows scale on x axis and y axis from 0 to 12 at increment
Ede4ka [16]

Nonlinear positive association

3 0
3 years ago
Read 2 more answers
Express the terms of the following geometric sequence recursively.
BabaBlast [244]

Answer:

The most correct option for the recursive expression of the geometric sequence is;

4. t₁ = 7 and tₙ = 2·tₙ₋₁, for n > 2

Step-by-step explanation:

The general form for the nth term of a geometric sequence, aₙ is given as follows;

aₙ = a₁·r⁽ⁿ⁻¹⁾

Where;

a₁ = The first term

r = The common ratio

n = The number of terms

The given geometric sequence is 7, 14, 28, 56, 112

The common ratio, r = 14/7 = 25/14 = 56/58 = 112/56 = 2

r = 2

Let, 't₁', represent the first term of the geometric sequence

Therefore, the nth term of the geometric sequence is presented as follows;

tₙ = t₁·r⁽ⁿ⁻¹⁾ = t₁·2⁽ⁿ⁻¹⁾

tₙ =  t₁·2⁽ⁿ⁻¹⁾ = 2·t₁2⁽ⁿ⁻²⁾ = 2·tₙ₋₁

∴ tₙ = 2·tₙ₋₁, for n ≥ 2

Therefore, we have;

t₁ = 7 and tₙ = 2·tₙ₋₁, for n ≥ 2.

4 0
3 years ago
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