Let f(x)=x^2 and g(x)=x-3. Find (fog)(-5). Please help!!!! Will fan and medal!!!

1 answer:

7 0

You might be interested in

What is the value of (3/10)3

Elenna [48]

Answer:

$\frac{9}{10}$

Step-by-step explanation:

In this question, one is asked to multiply a fraction by a whole number, first model the question.

$\frac{3}{10}(3)$

In a situation like this, one multiplies the whole number by the numerator (number) over the fraction.

$\frac{3*3}{10}$

Simplify,

$\frac{9}{10}$

A common error that people make is that they will multiply both the numerator and denominator by the whole number, this is the same as multiplying the answer by (1), thus it is incorrect.

6 0

2 years ago

8.71 ×<img src="https://tex.z-dn.net/?f=10%5E%7B7%7D" id="TexFormula1" title="10^{7}" alt="10^{7}" align="absmiddle" class="late

Semmy [17]

It’s 87100000 Have Ah Good Day.

4 0

2 years ago

Read 2 more answers

At what point is the following function continuous?

liubo4ka [24]

Check the picture below.

something worth noticing $\bf \cfrac{x^2-x-6}{x-3}\implies \cfrac{(\underline{x-3})(x+2)}{\underline{x-3}}\implies x+2$

so, we're really graphing x+2, with a hole at x = 3, however, when x = 3, we know that f(x) = 5, but but but, when x = 3, x+2 = 5, so we end up with a continuous line all the way, x ∈ ℝ, because the "hole" from the first subfunction, gets closed off by the second subfunction in the piece-wise.