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Nat2105 [25]
3 years ago
13

Let f(x)=x^2 and g(x)=x-3. Find (fog)(-5). Please help!!!! Will fan and medal!!!

Mathematics
1 answer:
astra-53 [7]3 years ago
7 0
<span>a. (f o g)(x)= f[g(x)] = f(x-5) = (x-5)^2
-----------------------------------------------
b. (g o f)(x)= g[f(x)] = g[x^2] = x^2-5
-------------------------------------------

c. (f o g)(-3) = f[g(-3)] = f[-8] = 64
---------------------
d. (g o f)(-3)= g[f(-3)] = g[9] = 4</span>
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The correlation coefficient of the data given in the table, using a calculator, is of 0.35

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To find the coefficient, we need to insert the points (x,y) in the calculator.

In this problem, we have that:

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6 0
3 years ago
Solve for x -<br><br><img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%2B%205x%20%2B%206%20%3D%200%20%5C%5C%20%5C%5C%20" id="T
Volgvan

Hello,

x² + 5x + 6 = 0

a = 1 ; b = 5 ; c = 6

∆ = b² - 4ac = 5² - 4 × 1 × 6 = 25 - 24 = 1 > 0

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x_{1} =  \frac{ - b -  \sqrt{\Delta} }{2a}  =  \frac{ - 5 - 1}{2 \times 1}  =  \frac{ - 6}{2}  =  - 3

x_{2} =  \frac{ - b  +   \sqrt{\Delta} }{2a}  =  \frac{ - 5  + 1}{2 \times 1}  =  \frac{ - 4}{2}  =  - 2

S = { -3 ; -2}

3 0
2 years ago
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