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Luden [163]
3 years ago
15

Please answer the question and shhow how you got your answer please

Mathematics
2 answers:
jonny [76]3 years ago
6 0

Answer: 0

Step-by-step explanation: Two of the numbers are both negative you’re going to want to add those together first. -17 + (-3) = -20. What’s left is -20 + 20 when you add a positive (20) with a negative (-20) you’re going to need to ‘subtract’ so sort of like this : 20 - 20 and that equals 0

bixtya [17]3 years ago
4 0
The answer is 7272837327373736379229838
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since it is in the tenths place, it'd be 6/10, or 6 tenths.

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<span><u>Answer </u>
31.12 in

<u>Explanation </u>
To get the length required, lets first find angle mF,
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Find a quadratic polynomial with integer coefficients which has x = 2/9, ± SQRT23/9 as its real zeros.
melomori [17]

Answer:

The quadratic polynomial with integer coefficients is y = 81\cdot x^{2}-36\cdot x -19.

Step-by-step explanation:

Statement is incorrectly written. Correct form is described below:

<em>Find a quadratic polynomial with integer coefficients which has the following real zeros: </em>x = \frac{2}{9}\pm \frac{\sqrt{23}}{9}<em>. </em>

Let be r_{1} = \frac{2}{9}+\frac{\sqrt{23}}{9} and r_{2} = \frac{2}{9}-\frac{\sqrt{23}}{9} roots of the quadratic function. By Algebra we know that:

y = (x-r_{1})\cdot (x-r_{2}) = x^{2}-(r_{1}+r_{2})\cdot x +r_{1}\cdot r_{2} (1)

Then, the quadratic polynomial is:

y = x^{2}-\frac{4}{9}\cdot x -\frac{19}{81}

y = 81\cdot x^{2}-36\cdot x -19

The quadratic polynomial with integer coefficients is y = 81\cdot x^{2}-36\cdot x -19.

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3 years ago
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Answer:

7 - n

Step-by-step explanation:

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