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3 years ago

I NEED THIS ANSWER ASAP!!

Mathematics

1 answer:

Greeley [361]3 years ago

4 0

A: 0 3 4 5 5 6 7 9 9 20
3 3 5 5 6 8 8 9 9

B: No, they are not symmetric

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What is the midpoint of (8,7) and (4,3)

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Hello! The midpoint of (8,7) and (4,3) Is (7.5, 3.5)

Hope this helps! And have a great day!

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3 years ago

What is the scale factor of the dilation?

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Answer:

divide by 2

Step-by-step explanation:

to go to 12 to 6 , you will have to divide by 2

12/2 = 6

12 and 6 are on the same side in both triangles , that is why I used those two numbers to figure out the scale factor

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3 years ago

Find the slope of the line that passes through (10, 5) and (5, 1)

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Answer:

4/5

Step-by-step explanation:

points: (10,5), (5,1)

(y2-y1)/(x2-x1)

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3 years ago

Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.005 signif

algol [13]

Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) $t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

e) $p_v =P(t_{118}$

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

$\bar X_{O}=2.91$ represent the mean for the Orange Coast

$\bar X_{C}=2.96$ represent the mean for the Coastline

$s_{O}=0.05$ represent the sample standard deviation for Orange Coast

$s_{C}=0.03$ represent the sample standard deviation for Coastline

$n_{O}=60$ sample size for Orange Coast

$n_{C}=60$ sample size for Coastline

$\alpha=0.005$ Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis: $\mu_{O} \geq \mu_{C}$

Alternative hypothesis: $\mu_{O} < \mu_{C}$

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

$t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=60+60-2=118$

Replacing the info we got:

$t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

Part e

We can calculate the p value with this probability:

$p_v =P(t_{118}$

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

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2 years ago

I need to write an even number between 7 and 16 draw a picture an them write a sentence to explain why it is an even number

serious [3.7K]

An even number is a number that is divisible by 2.
This means that dividing this number by 2 yields no remainder (the remainder is zero).

The even numbers between 7 and 16 are:
8 as 8/2 = 4 and remainder is zero
10 as 10/2 = 5 and remainder is zero
12 as 12/2 = 6 and remainder is zero
14 as 14/2 = 7 and remainder is zero

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3 years ago

Read 2 more answers