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3 years ago

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Takeisha is placing placemats around a table. Each placemat is 14 inches long and 10 inches wide. The rectangular table is 42 in

ches long and 48 inches wide. What is the greatest number of placemats that Takeisha can place around the table without overlapping?

1 answer:

Vesnalui [34]3 years ago

8 0

welll i kinda don get ur question but ummmm if u say like the graetest number then 48

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What is the slope of the line passing through the points (-5, 7) and (-3, 5)? -1/4 -1 1

Gnesinka [82]

Slope form is y/x
to find this subtract -5, 7 by -3, 5 to get
-2, 2 and putting it in slope format....2/-2 which would be -1 or just -x (means -1x)
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b is what we need to find now so... plug in one of the coordinates
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point) Covert the following integers from decimal notation to binary notation. (Do not put extra zeros in front of your binary n

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Answer:

The binary notation of the integer 234 is 11101010.

Step-by-step explanation:

To convert decimal to binary you must:

Divide the number by 2.
Get the integer quotient for the next iteration.
Get the remainder for the binary digit.
Repeat the steps until the quotient is equal to 0.
Write the remainders from bottom to top.

So, to convert the decimal number 234 to binary

$\left\begin{array}{ccc}\mathrm{Division\:by \:2}&\mathrm{Quotient}&\mathrm{Remainder}\\234/2&117&0\\117/2&58&1\\58/2&29&0\\29/2&14&1\\14/2&7&0\\7/2&3&1\\3/2&1&1\\1/2&0&1\end{array}\right$

The binary notation of the integer 234 is 11101010.

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2 years ago

What is five and one third divided by four

Stella [2.4K]

It is 1.3333333333 repeated

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3 years ago

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Suppose cos(x)= -1/3, where π/2 ≤ x ≤ π. What is the value of tan(2x). EDGE

AVprozaik [17]

Answer:

D

Step-by-step explanation:

We are given that:

$\displaystyle \cos x = -\frac{1}{3}\text{ where } \pi /2 \leq x \leq \pi$

And we want to find the value of tan(2<em>x</em>).

Note that since <em>x</em> is between π/2 and π, it is in QII.

In QII, cosine and tangent are negative and only sine is positive.

We can rewrite our expression as:

$\displaystyle \tan(2x)=\frac{\sin(2x)}{\cos(2x)}$

Using double angle identities:

$\displaystyle \tan(2x)=\frac{2\sin x\cos x}{\cos^2 x-\sin^2 x}$

Since cosine relates the ratio of the adjacent side to the hypotenuse and we are given that cos(<em>x</em>) = -1/3, this means that our adjacent side is one and our hypotenuse is three (we can ignore the negative). Using this information, find the opposite side:

$\displaystyle o=\sqrt{3^2-1^2}=\sqrt{8}=2\sqrt{2}$

So, our adjacent side is 1, our opposite side is 2√2, and our hypotenuse is 3.

From the above information, substitute in appropriate values. And since <em>x</em> is in QII, cosine and tangent will be negative while sine will be positive. Hence:

<h2> $\displaystyle \tan(2x)=\frac{2(2\sqrt{2}/3)(-1/3)}{(-1/3)^2-(2\sqrt{2}/3)^2}$ </h2>

Simplify:

$\displaystyle \tan(2x)=\frac{-4\sqrt{2}/9}{(1/9)-(8/9)}$

Evaluate:

$\displaystyle \tan(2x)=\frac{-4\sqrt{2}/9}{-7/9} = \frac{4\sqrt{2}}{7}$

The final answer is positive, so we can eliminate A and B.

We can simplify D to:

$\displaystyle \frac{2\sqrt{8}}{7}=\frac{2(2\sqrt{2}}{7}=\frac{4\sqrt{2}}{7}$

So, our answer is D.

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Answer:

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Step-by-step explanation:

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