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pychu [463]
3 years ago
15

Find the number for which: a. 20% is 16 b. 1.5% is 60

Mathematics
1 answer:
lidiya [134]3 years ago
7 0

Answer: 1) 80

2) 4000

Step-by-step explanation:

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D, Because the equation must be in slope intercept (y=mx+b) and since it is going upwards (all positive nunbers) then the slope would be positive as well. I hope this helps!
8 0
3 years ago
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Please help me with this and fast!
Serjik [45]

Answer:

16

5

O

I think

Step-by-step explanation:

7 0
3 years ago
Find the values of x:<br><br> I don’t understand how to do this please help
goblinko [34]

Answer:

x = 8

Step-by-step explanation:

11x - 34 and 7x - 2 are vertical angles and congruent, thus

11x - 34 = 7x - 2 ( subtract 7x from both sides )

4x - 34 = - 2 ( add 34 to both sides )

4x = 32 ( divide both sides by 4 )

x = 8

-----------------------

11x - 34 = 11(8) - 34 = 88 - 34 = 54

18y and 11x - 34 are adjacent angles and supplementary , thus

18y + 54 = 180 ( subtract 54 from both sides )

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y = 7

8 0
3 years ago
Assume that there are an equal number of births in each month so that the probability is that a person chosen at random was born
NikAS [45]

Answer:

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have a birthday in May, or they do not. The probability of a person having a birthday in May is independent of any other person. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of a person being in May:

May has 31 days in a year of 365. So

p = \frac{31}{365} = 0.0849

Group of 20 friends:

This means that n = 20

What is the probability that at the May celebration, exactly two members of the group have May birthdays?

This is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{20,2}.(0.0849)^{2}.(0.9151)^{18} = 0.2773

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

3 0
3 years ago
2. A bowling alley charges $3.00 to rent shoes and $1.50 per game bowled.
Zina [86]
3+1.50n would be an expression for this
6 0
3 years ago
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