Elliot has been running a lawn care business since 2000. He cuts grass, trims, and weed whacks yards for his customers throughou
t the season. Each year, he has increased his fee by the same amount. The table shows what Elliot charged each customer for two given years of his business: year Lawn Care Fee
2000 $750
2010 $1350
A. What is the rate of change and initial value for Elliot’s business? How do you know?
B. Write an equation in slope-intercept form to represent the fees that Elliot charges each year.
Alright, we know that the slope intercept form is y=mx+b, where x and y remain variables, m stands for the slope and b stands for the y intercept.
Because you should already have the slope from the first part (because slope is the same thing as rate of change), you should know that the slope is 60. The y-intercept should be your y value when x=0, and if you set up the equation in terms of years since Elliot has started his business, the year 2000 should be equal to x=0, so the y intercept should be equal to 750.
Now that you know the slope intercept form and what each part of it means, you can plug in what you have to get the final equation, which should be y=60x+750
She has 15 left because she had 28 then she at 3 which is now 25 then she gave 5 away which is 20 then she gave 5 more away which is 15. So she ends up with 15
