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Eva8 [605]
3 years ago
11

The cars are waiting in line for gas Nini is 9th front the front of the line and 20 from the back how many cars are on line for

the gas
Mathematics
1 answer:
vovangra [49]3 years ago
5 0
28 cars are on the line for gas.
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Give the domain and range. domain: {2, 0, 2}, range: {1, 0, 1}
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2√72 + 5√242 what is the answer for this question please can u tell me the right answer​
Radda [10]

Answer:

67\sqrt{2}

Step-by-step explanation:

Assuming you require to simplify the expression.

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplifying the radicals

\sqrt{72} = \sqrt{36(2)} = \sqrt{36} × \sqrt{2} = 6\sqrt{2}

\sqrt{242} = \sqrt{121(2)} = \sqrt{121} × \sqrt{2} = 11\sqrt{2}

Then

2\sqrt{72} + 5\sqrt{242}

= 2(6\sqrt{2} ) + 5(11\sqrt{2} )

= 12\sqrt{2} + 55\sqrt{2}

= 67\sqrt{2}

6 0
3 years ago
Anyone know what the answer is
Mars2501 [29]

Answer:

22,-15 ................ maybe

4 0
3 years ago
In how many ways can 3person study groups beselected from a class of 25students?Note: nrn!r!(n-r)!nEnter
nlexa [21]

Answer:

2,300

Explanation:

This is given as:

\begin{gathered} 25\text{ combination 3 represented as:} \\ ^nC_r=\frac{n!}{r!(n-r)!} \\ n=25 \\ r=3 \\ ^{25}C_3=\frac{25!}{3!(25-3)!} \\ ^{25}C_3=\frac{25\times24\times23\times22!}{3!\times22!} \\ ^{25}C_3=\frac{25\times24\times23}{3\times2\times1} \\ ^{25}C_3=2300 \end{gathered}

Therefore, there are 2,300 ways that 3 persons can be selected from 25 people

8 0
1 year ago
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