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Gala2k [10]
2 years ago
14

Which statement is true about the discontinuities of the function f(x)?

Mathematics
1 answer:
Leno4ka [110]2 years ago
8 0

Answer:

  (a)  There are asymptotes at x=3/2 and x=-1/3

Step-by-step explanation:

The denominator zeros can be found by factoring:

  f(x) = (x +1)/((2x -3)(3x +1))

Neither of the denominator factors is cancelled by the numerator factor, so each represents a vertical asyptote, not a function hole.

The asymptotes are at the values of x where the denominator is zero:

  2x -3 = 0   ⇒   x = 3/2

  3x +1 = 0   ⇒   x = -1/3

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Answer:

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Step-by-step explanation:

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7 0
3 years ago
Will give brainliest !please help <br><br>4b+7b+5​
Alecsey [184]

Answer:

Terms = 4b , 7b , 5

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Read 2 more answers
What is the contrapositive of the statement below?
algol13

Answer:

B. -y = -x

Step-by-step explanation:

When the values on both sides of the equal sign are changed, it becomes a negative number.

6 0
2 years ago
I need help: what is this?
givi [52]

Answer:

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Step-by-step explanation:

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3 years ago
For the function y = -2+5sin(pi/12(x-2)), what is the maximum value?
myrzilka [38]
To get the function y = <span>-2+5sin(pi/12(x-2)), the maximum value can be determined by differentiating the function and equating it to zero. The value of x will give the maximum value of the function.
dy/dx = 5 cos (pi/12 (x-2)) (pi/12)
dy/dx = 5 pi/12 cos(pi/12 (x-2))

Equate to zero</span>:
<span>5 pi/12 cos(pi/12 (x-2)) =0
pi/12 (x-2) = 3pi/2
x = 8

Substituting,
y= -2 + 5sin( pi/12 (8-2)
y = -1.86
</span>
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