Which statement is true about the discontinuities of the function f(x)?
1 answer:
Answer:
(a) There are asymptotes at x=3/2 and x=-1/3
Step-by-step explanation:
The denominator zeros can be found by factoring:
f(x) = (x +1)/((2x -3)(3x +1))
Neither of the denominator factors is cancelled by the numerator factor, so each represents a vertical asyptote, not a function hole.
The asymptotes are at the values of x where the denominator is zero:
2x -3 = 0 ⇒ x = 3/2
3x +1 = 0 ⇒ x = -1/3
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Answer:
option B
Step-by-step explanation:
Given in the question a complex fraction
<h3>Step1</h3>To divide complex numbers, you must multiply by the conjugate. To find the conjugate of a complex number all you have to do is change the sign between the two terms in the denominator.
Distribute (or FOIL) in both the numerator and denominator to remove the parenthesis.
Simplify the powers of i, specifically remember that i² = –1.
simply