Which statement is true about the discontinuities of the function f(x)?
1 answer:
Answer:
(a) There are asymptotes at x=3/2 and x=-1/3
Step-by-step explanation:
The denominator zeros can be found by factoring:
f(x) = (x +1)/((2x -3)(3x +1))
Neither of the denominator factors is cancelled by the numerator factor, so each represents a vertical asyptote, not a function hole.
The asymptotes are at the values of x where the denominator is zero:
2x -3 = 0 ⇒ x = 3/2
3x +1 = 0 ⇒ x = -1/3
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Answer:
The answer is .
Step-by-step explanation:
First, it is important to recall that the group law is not commutative in general, so we cannot assume it here. In order to solve the exercise we need to remember the axioms of group, specially the existence of the inverse element, i.e., for each element there exist another element, denoted by
such that
, where
stands for the identity element of G.
So, given the equality we make a left multiplication by
and we obtain:
But, . Hence,
.
Now, in the equality we make a right multiplication by
, and we obtain
.
Recall that and
. Therefore,
.