Anyone know the correct answer to this?

Mathematics

2 answers:

Svetllana [295]2 years ago

4 0

Answer:

It should be y=4x-7

Step-by-step explanation:

M is the slope meaning Δx over Δy or rise over run

So if you look at (2,2) and count up to (3,6) the rise is 4 and the run is 1 meaning the slope is 4.

B is the y- intercept so then it would just be -7.

Svetlanka [38]2 years ago

3 0

9514 1404 393Answer:

y=4x-6

Step-by-step explanation:

The line intersects the y-axis at y=-6, so that is the value of 'b' in the slope-intercept form.

The horizontal difference between marked points is 1 unit; the vertical difference is 4 units. That means the slope is . . .

m = rise/run = 4/1 = 4

Filling in these values (m=4, b=-6), we get ...

y = 4x -6

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What is the domain and range of the step function with the equation below? f(x) = -3[ x ]

TEA [102]

Answer:

Step-by-step explanation:

The domain is all real numbers, and the range is all integers that are multiples of 3. This is right I took the test.

7 0

3 years ago

Read 2 more answers

The following integral requires a preliminary step such as long division or a change of variables before using the method of par

shtirl [24]

Division yields

$\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}$

Now for partial fractions: you're looking for constants a, b, and c such that

$\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}$

$\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a$

which gives a + b = 2, c = 0, and 2a = -7, so that a = -7/2 and b = 11/2. Then

$\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}$

Now, in the integral we get

$\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx$

The first two terms are trivial to integrate. For the third, substitute y = x ² + 2 and dy = 2x dx to get

$\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}$