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Leokris [45]
3 years ago
13

Volume of prism 3cm base 10cm height

Mathematics
1 answer:
djverab [1.8K]3 years ago
5 0

30cm cubed the formula is v=bh


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(-5,-3) (5,5)<br> slope<br> What is the slope ?
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Answer:

The slope is 10/8

Step-by-step explanation:

You would rise 10 units and you would run 8 units.

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the base and height of the triangle at the right are multiplied by 4.Describe the change in the area.Justify your answer.
Dima020 [189]
I need more information about the triangle before I am able to answer your question.
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If ACFE = APTR, then ZF =
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What is the value of "c" in the following quadratic? (Make sure the equation is in
garri49 [273]

               \rule{50}{1}\large\blue\textsf{\textbf{\underline{Given question:-}}}\rule{50}{1}

           <em>What is the value of c in the quadratic </em>\large\text{$x^2+28=-11x$}?

          \rule{50}{1}\large\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

           Before starting to solve, you should notice something - the

quadratic is not in its standard form!

We can easily fix it by adding \large\textit{11x} on both sides:-

\large\text{$x^2+28-11x=0$}

We can switch the order of 28 and -11x:-

\large\text{$x^2-11x+28=0$}

  Now, the quadratic is in its standard form, so we can get down to

finding the value of "c".

Remember, the standard form of a quadratic looks like so:-

  •  \large\text{$ax^2+bx+c=0$}

Now we can just write our <u>quadratic</u> here:-

  • \large\text{$x^2-11x+28=0$}

Now, can you see what the value of "c" is?

An easy way to <u>remember</u> "c" in quadratics is:-

The "c" in quadratics is the constant.

   

Henceforth, we conclude that the value of "c" in the given quadratic is:-

 \Large\textbf{28}\Large\checkmark

<h3>         Good luck with your studies.</h3>

        \rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}    

5 0
2 years ago
Will give brain list!!! I need helppp! And show workk
Debora [2.8K]

Answer:

Dude! Stop telling people to do your work on DeltaMath

Step-by-step explanation:

6 0
3 years ago
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