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Ber [7]
3 years ago
14

1.Which expressions are polynomials? Select each correct answer. Pick more then one.

Mathematics
2 answers:
madreJ [45]3 years ago
6 0

If all the power of the variables are greater than or equal to zero, then the expression is a valid polynomial.

So,

1.

7x^{7}-x-5

35x^{2}

\frac{x}{5}+2

are polynomials.

2.

x^{2} -x\sqrt{2}

y

2 + s

4x^{2} +y

are all polynomials.

3.

If the degree of the polynomial is 3, then it is a cubic polynomial. If the number of terms of a polynomial is 3, then it is a trinomial.

Hence, -5x^{3}-4x+1 is a cubic trinomial.

4.

The highest power is the degree.

Hence, degree of the polynomial is 2 + 4 = 6.

Readme [11.4K]3 years ago
3 0
1. Polynomials are:
A ) 7 x^7 - x - 5
C ) 4 x + √ x - 1
D ) x/5 + 2

2. Polynomials are:
A ) x² - x √2
C ) 2 + s
D ) 4 x³ + y

3. The polynomial: - 5 x³ - 4 x + 1 is:
C ) Cubic trinomial.

4.  The degree of the polynomial: - 2 x² y^4 - 1/2 z is:
C ) 4
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Please Answer <br><br> This is due by tomorrow night and I need help
labwork [276]

Answer:

AY = 16

IY = 9

FG = 30

PA = 24

Step-by-step explanation:

<em>The </em><em>centroid </em><em>of the triangle </em><em>divides each median</em><em> at the ratio </em><em>1: 2</em><em> from </em><em>the base</em>

Let us solve the problem

In Δ AFT

∵ Y is the centroid

∵ AP, TI, and FG are medians

→ By using the rule above

∴ Y divides AP at ratio 1: 2 from the base FT

∴ AY = 2 YP

∵ YP = 8

∴ AY = 2(8)

∴ AY = 16

∵ PA = AY + YP

∴ AP = 16 + 8

∴ AP = 24

∵ Y divides TI at ratio 1: 2 from the base FA

∴ TY = 2 IY

∵ TY = 18

∴ 18 = 2

→ Divide both sides by 2

∴ 9 = IY

∴ IY = 9

∵ Y divides FG at ratio 1:2 from the base AT

∴ FY = 2 YG

∵ FY = 20

∴ 20 = 2 YG

→ Divide both sides by 2

∴ 10 = YG

∴ YG = 10

∵ FG = YG + FY

∴ FG = 10 + 20

∴ FG = 30

5 0
3 years ago
How many distinct triangles can be formed for which m∠E = 64°, g = 9, and e = 10?
zysi [14]

Answer:

1) one

2) zero

Step-by-step explanation:

e/sinE = g/sinG

10/sin64 = 9/sinG

sinG = 0.8089146417

G = 53.99

j/sinJ = k/sinK

3/sin129 = 8/sinK

sinK = 2.072389241

3 0
3 years ago
Read 2 more answers
1.) What is the equation of the path of firework #1? Write your equation in general form.
valina [46]

1. I'm assumig that the paths are perfect parabolas

this means that their general forms can be written in y=ax^2+bx+c

it's easier to find vertex form first then expand to get general form

vertex form is y=a(x-h)^2+k where the vertex is (h,k) and a is a constant


firework #1

vertex is (10,50), so (h,k)=(10,50) and h=10, k=50

h_1=a(t-10)^2+50

to find the value of a, subsitute another point

(0,0)

0=a(0-10)^2+50)

0=100a+50

a=\frac{-1}{2}

so the equation in vertex form is h_1=\frac{-1}{2}(t-10)^2+50

expand to get general form

h_1=\frac{-1}{2}(t^2-20t+100)+50

h_1=\frac{-1}{2}t^2+10t-50+50

h_1=\frac{-1}{2}t^2+10t





2.

same as last time

vertex is (10,72) so (h,k)=(10,72) so h=10 and k=72

equation is h_2=a(t-10)^2+72

find a

use another point

(0,22)

22=a(0-10)^2+72

22=100a+72

-50=100a

a=\frac{-1}{2}

so the equation in vertex form is h_2=\frac{-1}{2}(t-10)^2+72




3.

range is the numbers that h is allowed to be

think about what h represents. it represents the height of the rocket

from the graph, we can see that the lowest possible height is 0yd and the highest height is 50yd

so range is 0 to 50 or 0≤h≤50


domain is the numbers that t is allowed to be

think about what t represents. it represents how long the rocket has been flying

it will stop flying when it hits the ground or at t=20

it starts flying at t=0

so domain is from 0 to 20 or 0≤t≤20

3 0
3 years ago
The ratio of girls to boys in Liza’s classroom is 5
alexira [117]
There are 15 girls in the classroom
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Dominic and Terrell plan to start their weekend backpacking trip on Friday at 4:20 P.M, and return home on Sunday at 5:40 A.M. H
Aleonysh [2.5K]

I think the answer is 4.20 hours and minutes planning the last road trip .

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