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3 years ago

What is the tithe of an income of $97.50

Mathematics

1 answer:

vitfil [10]3 years ago

6 0

Since tithe is 10% of what you receive, the answer is $9.75

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Tom had a board that was 4 ft. 5 in. long. He cut off a piece that was 1 ft. 9 in long. How much board does he have left?

EastWind [94]

It’s c your welcome make me Brainly

8 0

3 years ago

Friday, a store sold 10 blue shirts and 20 white shirts. what percentage of the shirts sold were blue? give answer to the ones p

jasenka [17]

Answer:

10+20=30

10 is what percent of 30?

10 is 1/3 of 30

Step-by-step explanation:

10 is 33.33% of 30

so 33% of the shirts sold were blue

6 0

3 years ago

LINEAR EQUATIONS PLZ HELP BRAINLIEST AND EXTRA POINTS!!!

Oliga [24]

Answer:

1) B) a = 14

2)D) x = -11

3)B) x = 8

4)A) 250 = 3c-20

5)D)8

6)B), C), D)

8)A) 14 months

9)Sarah = 40 years

Sarah = 5/4 x Tanya

40 = 5/4 x Tanya's age

Therefore Tanya's age is 32 years old

Hope this helps you!

4 0

3 years ago

Read 2 more answers

What is the answer to 2a-3=7

ladessa [460]

2a−3=7

Add 3 to both sides.

2a−3+3=7+3

2a=10

Divide both sides by 2.

2a / 2 = 10 / 2

a=5

5 0

3 years ago

A cooler contains fifteen bottles of sports drink: eight lemon-lime flavored and seven orange flavored

dem82 [27]

Answer:

Mutually exclusive,

$P(\text{Lemon-lime or orange})=\frac{2}{3}$

Step-by-step explanation:

Please consider the complete question:

Determine if the scenario involves mutually exclusive or overlapping events. Then find the probability.

A cooler contains twelve bottles of sports drink: four lemon-lime flavored, four orange flavored, and four fruit-punch flavored. You randomly grab a bottle. It is a lemon-lime or an orange.

Let us find probability of finding one lemon lime drink.

$P(\text{Lemon-lime})=\frac{\text{Number of lemon lime drinks}}{\text{Total drinks}}$

$P(\text{Lemon-lime})=\frac{4}{12}$

$P(\text{Lemon-lime})=\frac{1}{3}$

Let us find probability of finding one orange drink.

$P(\text{Orange})=\frac{\text{Number of orange drinks}}{\text{Total drinks}}$

$P(\text{Orange})=\frac{4}{12}$

$P(\text{Orange})=\frac{1}{3}$

Since probability of choosing a lemon lime doesn't effect probability of choosing orange drink, therefore, both events are mutually exclusive.

We know that probability of two mutually exclusive events is equal to the sum of both probabilities.

$P(\text{Lemon-lime or orange})=P(\text{Lemon-lime})+P(\text{Orange})$

$P(\text{Lemon-lime or orange})=\frac{1}{3}+\frac{1}{3}$

$P(\text{Lemon-lime or orange})=\frac{1+1}{3}$

$P(\text{Lemon-lime or orange})=\frac{2}{3}$

Therefore, the probability of choosing a lemon lime or orange is $\frac{2}{3}$ .

8 0

3 years ago