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2 years ago

7

Precious spends $4 on a magazine at a newsstand. When leaving the newsstand, she finds a quarter on the sidewalk. How much money

does Precious have now compared to when she first arrived at the newsstand?
I NEED TO KNOW

1 answer:

jeka57 [31]2 years ago

7 0

Well now she has $4.25 lol. She had $4 then, now she has $4.25.

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wich is the biggest number in the world from 1.2.3.4.5.6.7.8.9 wich one of these numbers you think is bigger be careful ?

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Answer: nine and if its a joke i have no clue

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3 years ago

Your friend says that there are 36 feet in 12 yards. Is your friend correct? Explain your reasoning?

vesna_86 [32]

Answer:

Step-by-step explanation:

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3 years ago

Seed corn was $5 per bag, whereas dog food cost only $3 per bag. Wewoka bought 50 bags and spent $190. How many bags of dog food

Anuta_ua [19.1K]

Hello!

You can make two equations based on what you know

x + y = 50
5x + 3y = 190

Subtract y from both sides of the first equation

x = 50 - y

Put x into the second equation

5(50 - y) + 3y = 190

Distribute the 5

250 - 5y + 3y = 190

Combine like terms

250 - 2y = 190

Subtract 250 from both sides

-2y = -60

Divide both sides by -2

y = 30

Put y into the first equation

x + 30 = 50

Subtract 30 from both sides

x = 20

She bought 20 seed corn bags and 30 bags of dog food

Hope this helps!

8 0

3 years ago

Read 2 more answers

Please answer a and c

n200080 [17]

add the numbers on both side by 3

4 + 3 = 7

8 + 3 = 11

rewrite the expression

7<11

that is still true

do the same by multiplying it by 2 and rewrite the inequality

5 0

3 years ago

I need help on these questions please

Paraphin [41]

Answer:

Step-by-step explanation:

1). In ΔABC,

For angle A as a reference angle,

Opposite side of ∠A → BC

Adjacent side of ∠A → AC

Hypotenuse → AB

2). By using tangent ratio in ΔYWZ,

tan(72°) = $\frac{\text{Opposite side}}{\text{Adjacent side}}$

tan(72°) = $\frac{12}{x}$

x = $\frac{12}{\text{tan}(72)}$

x = 3.899

x ≈ 3.9

3). By using sine rule in ΔKNM,

tan(x°) = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

tan(x) = $\frac{20}{58}$

x = $\text{tan}^{-1}(\frac{20}{58} )$

x = 19.03

x ≈ 19.0°

4). By applying cosine ratio in ΔJKF,

tan(70°) = $\frac{\text{Opposite side}}{\text{Adjacent side}}$

tan(70) = $\frac{60}{x}$

x = $\frac{60}{\text{tan}(70)}$

x = 21.838

x ≈ 21.8

7 0

3 years ago