Answer:
Step-by-step explanation:
The 20th of February for seven nights:
Mr. Jones: 714
Mrs. Jones: 714
Child 1: 95% of 714 = 678.30
Child 2: 95% of 714 = 678.30
Total Price: 2784.60
The 10th of April for fourteen nights:
Mr. Jones: 802
Mrs. Jones: 802
Child 1: 85% of 802 = 681.70
Child 2: 85% of 802 = 681.70
Total Price: 2967.40
The 10th of April for fourteen nights is 182.80 pounds greater than the 20th of February for seven nights.
Answer:
In the coordinate plane we can draw the translation if we know the direction and how far the figure should be moved. To translate the point P(x,y) , a units right and b units up, use P'(x+a,y+b) .
Step-by-step explanation:
Answer: 2.25 km
Step-by-step explanation:
2 cm = 0.5 km
9 cm = (9 x 0.5)/2
= 2.25 km
<span><span>
The correct answers are:</span><span>
(1) The vertical asymptote is x = 0
(2) The horizontal asymptote is y = 0
</span><span>
Explanation:</span><span>(1) To find the vertical asymptote, put the denominator of the rational function equals to zero.
Rational Function = g(x) = </span></span>

<span>
Denominator = x = 0
Hence the vertical asymptote is x = 0.
(2) To find the horizontal asymptote, check the power of x in numerator against the power of x in denominator as follows:
Given function = g(x) = </span>

<span>
We can write it as:
g(x) = </span>

<span>
If power of x in numerator is less than the power of x in denomenator, then the horizontal asymptote will be y=0.
If power of x in numerator is equal to the power of x in denomenator, then the horizontal asymptote will be y=(co-efficient in numerator)/(co-efficient in denomenator).
If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.
In above case, 0 < 1, therefore, the horizontal asymptote is y = 0
</span>
Answer:
II. Longitud, L = 70 metros.
I. Ancho = 55 metros.
Step-by-step explanation:
Deje que la longitud del rectángulo sea L.
Deje que el ancho del rectángulo sea W.
Dados los siguientes datos;
Perímetro del rectángulo = 250 m
Traduciendo el problema verbal a una expresión algebraica, tenemos;
W = L - 15
Matemáticamente, el perímetro de un rectángulo viene dado por la fórmula;
P = 2 (largo + ancho)
250 = 2 (L + L - 15)
250 = 2 (2L - 15)
250 = 4L - 30
4L = 250 + 30
4L = 280
L = 280/4
Longitud, L = 70 m
Para encontrar el ancho;
W = L - 15
W = 70 - 15
Ancho = 55 m