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Arisa [49]
2 years ago
15

Help me fast please.

Mathematics
2 answers:
Valentin [98]2 years ago
8 0
Y= -6x+ 4 is going to be your answer
Harman [31]2 years ago
3 0

Answer:

the answer would be (-4,-6)

Step-by-step explanation:

hope this helps ya

good luck!!!!!

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What is the cube of 8?<br> O A. 2<br> O B. 64<br> C.53<br> O D. 24
VMariaS [17]

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Step-by-step explanation:

8 0
2 years ago
Find the distance of a line given the following points. R(3, 1), W(-1, -2)
olga_2 [115]

Answer:

5 units

Step-by-step explanation:

±√(- 2 - 1)^2 + (- 1 - 3)^2 = ±5 (rej - 5 since distance > 0)

Apply distance formula

This is a topic on coordinate geometry. If you would like to find out more you can give my Instagram page a follow as I'll be updating on this topic soon. In addition, I will be posting other useful materials created by myself at the same platform too!

7 0
2 years ago
O. días. m dificultad<br> +1. +28. -56. -1<br> -9. x. 63+. +2
mihalych1998 [28]

Answer:

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Step-by-step explanation:

4 0
3 years ago
The height of a tennis ball tossed into the air is modeled by h(x) = 40x â€" 16x 2, where x is elapsed time in seconds. During w
egoroff_w [7]

The time interval x >0.5 and x > 2.04 will the tennis ball be at least 15 feet above the ground.

Given that,

The height of a tennis ball tossed into the air is modeled by,

\rm h(x) = 40x - 16x^2

Where x is elapsed time in seconds.

We have to determine,

During what time interval will the tennis ball be at least 15 feet above the ground?

According to the question,

The height of a tennis ball tossed into the air is modeled by,

\rm h(x) = 40x - 16x^2

Where x is elapsed time in seconds.

Then,

When the tennis ball be at least 15 feet above the ground,

h(x) = 15

Substitute the value of h(x) in the equation,

\rm h(x) = 40x - 16x^2\\\\ 15 = 40x - 16x^2\\\\ 16x^2-40x+15=0

Factorize the equation for finding the time interval will the tennis ball be at least 15 feet above the ground is,

\rm 16x^2-40x+15= 0\\\\x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\x = \dfrac{-(-40)\pm \sqrt{(-40)^2-4 \times 16 \times 15}}{2 \times 16}\\\\x =  \dfrac{-(-40)\pm \sqrt{1600- 960}}{32}\\\\x =  \dfrac{40\pm \sqrt{640}}{32}\\\\x =  \dfrac{40 + 25.29}{32} \\\\x =  \dfrac{40 + 25.29}{32} \ and \ x =  \dfrac{40 - 25.29}{32}\\\\x = \dfrac{65.29}{32} \ and \ x = \dfrac{14.71}{32}\\\\x = 2.04 \ and \ x = 0.45

Hence, The time interval x >0.5 and x > 2.04 will the tennis ball be at least 15 feet above the ground.

For more details about Inequality refer to the link given below.

brainly.com/question/17177510

7 0
2 years ago
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