If an items weight is 0 it would be like a peice of paper or cotten ball. when a cotten ball is weighed it does not affect anything. as when a peice of paper is wieghed it moves its meater 1 inch.
First simplify 3x + 12 - 6x to -3x - 12
Next subtract 12 from both sides
Next subtract -9 - 12 and that would be -21
Next divide both sides by -3
Next lets simplify the fraction -21/-3 into 21/3 since those two negatives make a positive.
Lastly simplify the fraction 21/3 to get the answer.
Answer: x ≥ 7
Average= f(2)−f(0)/2−0
=62.5−250/ 2-0
<span>= −93.75</span>
Answer:
<h2>4</h2>
Step-by-step explanation:
Answer:
Step-by-step explanation:
First confirm that x = 1 is one of the zeros.
f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26
f(1) = 2 - 14 + 38 - 26
f(1) = -12 + 38 = + 26
f(1) = 26 - 26
f(1) = 0
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next perform a long division
x -1 || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26
2x^3 - 2x^2
===========
-12x^2 + 28x
-12x^2 +12x
==========
26x -26
26x - 26
========
0
Now you can factor 2x^2 - 12x + 26
2(x^2 - 6x + 13)
The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16
So you are going to get a complex result.
x = -(-6) +/- sqrt(-16)
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2
x = 3 +/- 2i
f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)
The zeros are
1
3 +/- 2i
