Pedro must make $330 on the 6th day to have a mean average of $200.
Step-by-step explanation:
<u>Formula for Mean Average</u>
Mean Average =
<u>DATA:</u>
1st day = $120
2nd day = $110
3rd day = $200
4th day = $300
5th day = $140
6th day = x
<u>Solution:</u>
Mean Average =
200 =
200*6 = 870+x
1200 - 870 = x
x = 330
Pedro must make $330 on the 6th day to have a mean average of $200.
Keyword: Mean
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Answer:
(a) The probability that a randomly selected adult is either overweight or obese is 0.569.
(b) The probability that a randomly selected adult is neither overweight nor obese is 0.431.
Step-by-step explanation:
Let <em>A</em> = a person is over weight and <em>B</em> = a person is obese.
The information provided is:
An adult is considered overweight if the BMI ≥ 25 but BMI < 30.
An obese adult will have a BMI ≥ 30.
According to the range of BMI the events A and B are independent.
P (A) = 0.331 and P (B) = 0.357.
(a)
Compute the probability that a randomly selected adult is either overweight or obese as follows:
P (A ∪ B) = P (A) + P (B) - P (A ∩ B)
= P (A) + P (B) - P (A)×P (B)
Thus, the probability that a randomly selected adult is either overweight or obese is 0.569.
(b)
Compute the probability that a randomly selected adult is neither overweight nor obese as follows:
Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.431.
Answer:
x = -4/3 and x = 5/2.
Step-by-step explanation:
6x² - 7x = 20
6x² - 7x - 20 = 0
To solve this, we can use the quadratic formula to solve this.
[please ignore the A-hat; that is a bug]
In this case, a = 6, b = -7, and c = -20.
=
=
=
=
=
= -8 / 6 = -4 / 3
=
= 15 / 6 = 5 / 2
So, x = -4/3 and x = 5/2.
Hope this helps!