Answer:
52% and 7
Step-by-step explanation:
There are 25 squares of which 13 are shaded , then
× 100% = 13 × 4% = 52°
(b)
1 square represents
× 100% = 1 × 4% = 4%
Then 80% = 80% ÷ 4% = 20
That is for 80% , 20 squares require to be shaded
That is 7 more than the 13 already shaded
Answer:
The length of the sides of the square is 9.0015
Step-by-step explanation:
Given
The diagonal of a square = 12.73
Required
The length of its side
Let the length and the diagonal of the square be represented by L and D, respectively.
So that
D = 12.73
The relationship between the diagonal and the length of a square is given by the Pythagoras theorem as follows:

Solving further, we have

Divide both sides by 2


Take Square root of both sides


Reorder

Now, the value of L can be calculated by substituting 12.73 for D




(Approximated)
Hence, the length of the sides of the square is approximately 9.0015
Answer:
Step-by-step explanation:
If you divide 2,727 miles by 27 miles per gallon you will get the number of gallons: = 101. Then, multiply the number of gallons by the cost per gallon: 101(4.04) = 408.04. This gives the cost of gas for this car to travel 2,727 typical miles.
Answer:
both statement have valid conclusions.
Step-by-step explanation:
A rhombus is a parallelogram with all sides equal.
A parallelogram has opposite angles congruent.
Therefore
both statements have valid conclusions.
Mr. Mole's burrow was at an altitude of 6 meters below the ground.
Step-by-step explanation:
Step 1:
We need to determine the distance that Mr. Mole covers in a single minute.
To do that we divide the difference in values of altitude by the difference in the time periods.
For the first case, Mr. Mole had traveled -18 meters in 5 minutes.
We also have, he traveled -25.2 meters in 8 minutes.
Step 2:
The distance he covered in 1 minute 

So with every minute, Mr. Mole digs down an additional 2.4 meters below the surface.
To determine where Mr. Mole's burrow is we subtract the distance traveled in 5 minutes from -18.
The altitude of Mr. Mole's burrow 
So Mr. Mole's burrow was at an altitude of 6 meters below the ground i.e. -6 meters.