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3 years ago

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If f(x) is 3x^2 - 2x +1 what is f(x)+f(2)

1 answer:

ArbitrLikvidat [17]3 years ago

8 0

Hello!

In this problem, we are using function arithmetic.

The term f(x) is given, which is 3x² - 2x + 1.

The term f(2) is not given, but we know half of what the function is asking for. The function of f is 3x² - 2x + 1, but we are needed to find f(2). This means we substitute x = 2 into f(x). After that, combine like terms.

f(x) + f(2)

3x² - 2x + 1 + 3(2)² - 2(2) + 1 (multiply)

3x² - 2x + 1 + 12 - 4 + 1 (simplify)

3x² - 2x + 10

Therefore, f(x) + f(2) is 3x² - 2x + 10.

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Find the absolute maximum and minimum values of the function below. f(x) = x3 − 9x2 + 3, − 3 2 ≤ x ≤ 12 Solution Since f is cont

Neko [114]

Answer:

There are an absolute minimum (x = 6) and an absolute maximum (x = 12).

Step-by-step explanation:

The correct statement is described below:

Find the absolute maximum and minimum values of the function below:

$f(x) = x^{3}-9\cdot x^{2}+ 3$ , $2 \leq x \leq 12$

Given that function is a polynomial, then we have the guarantee that function is continuous and differentiable and we can use First and Second Derivative Tests.

First, we obtain the first derivative of the function and equalize it to zero:

$f'(x) = 3\cdot x^{2}-18\cdot x$

$3\cdot x^{2}-18\cdot x = 0$

$3\cdot x \cdot (x-6) = 0$ (Eq. 1)

As we can see, only a solution is a valid critical value. That is: $x = 6$

Second, we determine the second derivative formula and evaluate it at the only critical point:

$f''(x) = 6\cdot x -18$ (Eq. 2)

x = 6

$f''(6) = 6\cdot (6)-18$

$f''(6) =18$ (Absolute minimum)

Third, we evaluate the function at each extreme of the given interval and the critical point as well:

x = 2

$f(2) = 2^{3}-9\cdot (2)^{2}+3$

$f(2) = -25$

x = 6

$f(6) = 6^{3}-9\cdot (6)^{2}+3$

$f(6) = -105$

x = 12

$f(12) = 12^{3}-9\cdot (12)^{2}+3$

$f(12) = 435$

There are an absolute minimum (x = 6) and an absolute maximum (x = 12).

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I will give brainiest if random will report please include the expression in answer

Mandarinka [93]

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Plz give me brainlest

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