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nekit [7.7K]
3 years ago
8

What is the solution of -8/2y-8=5/y+4-7y+8/y^2-16 y = –4 y = –2 y = 4 y = 6

Mathematics
2 answers:
maria [59]3 years ago
4 0
(-8)/(2y-8)=(5/(y+4))-7y+(8/(y^2-16))
(-4)/(y-4)=(5/(y+4))-7y+(8/(y+4)(y-4))
((-4)(y+4))/((y+4)(y-4))=((5(y-4))/(y+4)(y-4))-(7y(y+4)(y-4))/(y+4)(y-4))+(8/(y+4)(y-4))
(-4(y+4))=(5(y-4))-(7y(y+4)(y-4))+8
-4y-16=5y-20-(7y(y^2-16))+8
-4y-16=5y-20-7y^3+112y+8
-4y-16=117y-7y^3-12
-4=(121-7y^2)(y)
None of these choices would be equal to -4

Fittoniya [83]3 years ago
4 0

Answer:

The answer is <em><u>y=6</u></em>!

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=> <span>m∠2 = 2x +13
=> </span><span><span>m∠1 = </span> 4x - 1
Since YP angle bisector the angles with be equal to each other,
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m∠1 = <span>m∠2
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