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3 years ago

9

If it takes 4 men 6 hours to repair a road, How long will it take 3 men to do the job if they work at the same rate ? A) 5 hours

B) 6 hours C) 8 hours D) 9 hours

1 answer:

ch4aika [34]3 years ago

3 0

Answer is <span>C) 8 hours

hope it helps</span>

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Ahmed, Walid and Faisal made $1446 profit from selling used books. If Ahmed to receive double amount of Faisal and Walid to rece

crimeas [40]

Answer:

Faisal receives $241

Ahmed receives $482

Walid receives $723

Step-by-step explanation:

I am going to build a system of equations to solve this question.

We have that:

x is the amount that Faysal received.

y is the amount that Ahmed received.

z is the amount that Walid received.

Ahmed, Walid and Faisal made $1446 profit from selling used books.

This means that

$x + y + z = 1446$

Ahmed to receive double amount of Faisal

This means that $y = 2x$

Walid to receive triple amount of Faisal.

This means that $z = 3x$

So

$x + 2x + 3x = 1446$

$6x = 1446$

$x = \frac{1446}{6}$

$x = 241$

$y = 2x = 2*241 = 482$

$z = 3x = 3*241 = 723$

Faisal receives $241

Ahmed receives $482

Walid receives $723

8 0

3 years ago

What is the slope of the line that passes through the points (-2.15) and (-8,-5)?

Savatey [412]

Slope = 20/6 = 10/3

......................................

5 0

2 years ago

Read 2 more answers

Based on a sample of 100 employees a 95% confidence interval is calculated for the mean age of all employees at a large firm. Th

babymother [125]

Answer:

a

$\= x = 40.85$

b

$E = 5.85$

Ca

$t_c = 2.08$

Cb

$t_c = 1.282$

Explanation:

From the question we are told that

The sample size is n = 100

The upper limit of the 95% confidence interval is b = 47.2 years

The lower limit of the 95% confidence interval is a = 34.5 years

Generally the sample mean is mathematically represented as

$\= x = \frac{a + b }{2}$

=> $\= x = \frac{47.2 + 34.5 }{2}$

=> $\= x = 40.85$

Generally the margin of error is mathematically represented as

$E = \frac{b- a }{ 2}$

=> $E = \frac{47.2- 34.5 }{ 2}$

=> $E = 5.85$

Considering question C a

From the question we are told the confidence level is 90% , hence the level of significance is

$\alpha = (100 - 90 ) \%$

=> $\alpha = 0.10$

The sample size is n = 22

Given that the sample size is not sufficient enough i.e $n < 30$ we will make use of the student t distribution table

Generally the degree of freedom is mathematically represented as

$df = n- 1$

=> $df = 22 - 1$

=> $df = 21$

Generally from the student t distribution table the critical value of $\frac{\alpha }{2}$ at a degree of freedom of 21 is

$t_c =t_{\frac{\alpha }{2} , 21 } = 2.08$

Considering question C b

From the question we are told the confidence level is 80% , hence the level of significance is

$\alpha = (100 - 80 ) \%$

=> $\alpha = 0.20$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$t_c =Z_{\frac{\alpha }{2} } = 1.282$

4 0

3 years ago

In 1992, the moose population in a park was measured to be 3570. By 1999, the population was measured again to be 3640. If the p

JulijaS [17]

Answer:

The formula for the moose population is

$P=10t+3550$

Step-by-step explanation:

In 1992—that is, 2 years after 1990 or at $t=2$ —the population $P$ is 3570, and in 1999 ( $t=9$ ) population is 3640; so we have

$t=2,P=3570\\t=9,P=3640$

Now the formula that will model the moose population will be of the form:

$P=mt+b$

The slope $m$ is

$m=\frac{3640-3570}{9-2} =10$

therefore we have

$P=10t+b$

Now we know that at $t=2,$ $P=3570$ , so we put these values in and solve for $b:$

$3570=10(2)+b$

$b=3550$

With this value of $b$ , we finally have the formula for the moose population:

$\boxed{P=10t+3550}$

6 0

3 years ago

What is the exact value of tan(3009)?

Sergio039 [100]

Answer:

-sqrt(3)

Step-by-step explanation:

If you type in your calculator, you'll get -1.732050808... which is the negative of sqrt(3)

4 0

3 years ago