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adoni [48]
4 years ago
13

Analyze the diagram below and complete the instructions that follow:

Mathematics
2 answers:
olga_2 [115]4 years ago
4 0

Answer:

Answer is D

Step-by-step explanation:

The answer is D because CFE is 90*... it mentions that angle AFB is 23* so all I did was do 180 - 23 = 157.

swat324 years ago
3 0
M<CDE = <CFD and <EFD = 90
<EFD = <BFC
<CFD = <AFB

m<EFB = <BFC + <CDE
m<EFB = 69 + 90
m<EFB = 159
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Can someone help me
worty [1.4K]

Answer:

B = 129

Step-by-step explanation:

Opposite angles of a parallelogram are equal (or congruent)

A and C are both 51.

All angles in a parallelogram equal 360

Take both the known angles and substract from 360, than divide by 2.

B = (360 - 51 - 51)/2

B = 129

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3 years ago
In Exercises 5-8, find the perimeter and area of the polygon with the given vertices.
castortr0y [4]

Check the picture below.

as  we can see in the picture, the lengths for YZ and ZX are very straight, let's get the side YX

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Find LCM of:<br><br>x2 - 9, 3x3 + 81​
VikaD [51]

Answer:

\boxed{\pink{\sf (x + 3) \ is\ the \ LCM . }}

Step-by-step explanation:

Given two expressions ,

\qquad (1)\: x^2 - 9 \\\\ \qquad (2)\:3x^3 + 81

And , we need to find the LCM , that is lowest common factor . So , let's factorise them seperately .

<u>Factorising</u><u> </u><u>x²</u><u> </u><u>-</u><u> </u><u>9</u><u> </u><u>:</u><u>-</u><u> </u>

= x^2 - 9 \\\\= x^2 - 3^2 \\\\ \red{= (x+3)(x-3)} \qquad\bf [Using \ a^2-b^2 = (a+b)(a-b) ]

<u>Factorising</u><u> </u><u>3x</u><u>³</u><u> </u><u>+</u><u> </u><u>8</u><u>1</u><u> </u>

= 3x^3 + 81\\\\= 3(x^3+27) \\\\= 3( x^3+27) \\\\ = 3(x^3+3^3) \\\\ \red{= 3 [ (x+3)(x^2+9-3x) ] } \qquad \bf{[ Using \ a^3+b^3=(a+b)(a^2+b^2-ab) ] }

Hence we can see that (x+3) is common factor in both expressions.

<u>Hence</u><u> </u><u>the</u><u> </u><u>LCM</u><u> </u><u>is</u><u> </u><u>(</u><u> </u><u>x</u><u>+</u><u>3</u><u> </u><u>)</u><u> </u><u>.</u>

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