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3 years ago

Write each of the numbers 1,8,27,64, and 125 as a based raised to the third power

Mathematics

1 answer:

KatRina [158]3 years ago

6 0

$1 = {1}^{3 } \\ 8 = {2}^{3} \\ 27 = {3}^{3} \\ 64 = {4}^{3}$
$125 = {5}^{3}$

good luck

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aleksandr82 [10.1K]

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3 years ago

A triangle has a 60° angle, and the two adjacent sides are 12 and "12 times the square root of 3". Find the radius of a circle w

shusha [124]

The radius of a circle with the same vertex as a center is 12 units

<h3>Application of Pythagoras theorem;</h3>

To get the radius of the circle, we need to determine the diameter of the circle first:

According to SOH CAH TOA:

$sin\theta = \frac{opp}{hyp} \\sin60 = \frac{12\sqrt{3}}{hyp} \\hyp =\frac{12\sqrt{3}}{sin60} \\hyp =\frac{2\times12\sqrt{3}}{\sqrt3}} \\hyp = 24 = diameter$

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Radius = 12

Hence the radius of a circle with the same vertex as a center is 12 units

Learn more on radius of a circle here: brainly.com/question/24375372

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2 years ago

fifteen out of the 60 eighth-graders at sebring junior high are on the track team. what percent of the eight-graders are on the

allsm [11]

Answer:

25%

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3 years ago

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

kozerog [31]

Answer: 49.85%

Step-by-step explanation:

Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.

i.e. $\mu=61$ and $\sigma=9$

To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.

i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and $34+3(9)$ .

i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between $\mu$ and $\mu+3(\sigma)$ . (1)

According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.

i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.

i.e.,The approximate percentage of lightbulb replacement requests numbering between $\mu$ and $\mu+3(\sigma)$ = 49.85%

⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%

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3 years ago

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cluponka [151]

Answer:

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