Question

Which point is in the solution set of the given system of inequalities 3x+y>-3,x+2y<4

Answer 1

Step 1. Solve both inequalities for $y$:
$3x+y\ \textgreater \ -3$
$y\ \textgreater \ -3x-3$

$x+2y\ \textless \ 4$
$2y\ \textless \ -x+4$
$y\ \textless \ - \frac{1}{2} x+2$

Step 2. To check a point in the solution of the given system of inequalities, look for the intercepts of the lines $-3x-3$ and $- \frac{1}{2} x+2$:

$y=-3x-3$ (1)
$y=- \frac{1}{2} x+2$ (2)

Replace (1) in (2):
$-3x-3=- \frac{1}{2} x+2$
Solve for $x$:
$\frac{5}{2} x=-5$
$x=-2$ (3)

Replace (3) in (1):
$y=-3x-3$
$y=-3(-2)-3$
$y=6-3$
$y=3$

We can conclude that the point (-2,3) is in the solution of the system if inequalities; also any point inside the dark shaded area of the graph of the system of inequalities is also a solution of the system.

Answer 2

The closest answer is B. -2,0