It depends on the variable.
If it's something like x < 2, your graph would be a vertical line at x = 2, and everything to left of that line shaded in (because of the less than).
Similarly for y, except it would be a horizontal line with either everything above or below shaded.
You can have other equations like 0<x<4 where everything between x = 0 and x = 4 would be shaded
Answer: 5
Step-by-step explanation:
Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
Answer:
they match with each other
A -1
B-2
C-3
Step-by-step explanation:
