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jek_recluse [69]
3 years ago
15

Is the product of two integers positive, negative, or zero?

Mathematics
1 answer:
Delvig [45]3 years ago
6 0
If they both have the same signal than its positive if not its negative. I don't what you mean by zero though i'm in 6th grade
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Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit
coldgirl [10]
Changing the equation into slope form: y = mx + c, where m is the slope [gradient] and c is the y-intercept.

2x+3y=1470
3y = -2x+1470
y= - \frac{2}{3}x+ \frac{1470}{3}
y=- \frac{2}{3}x+490

The gradient is - \frac{2}{3} and y-intercept is at y=490

Graphing y=- \frac{2}{3}x+490 using slope-intercept method:
a) The slope is a negative slope. The line will go 'down hill'
b) The line must pass the point (0, 490)
c) The line will intercept the x-axis at y = 0
    0 = - \frac{2}{3}x+490
    \frac{2}{3}x = 490
    2x = 1470
    x = \frac{1470}{2}
    x = 735
    So, x-intercept is at (735, 0)

The graph of this function is shown below. The intercepts are labelled at:
y = 490
x = 735

-----------------------------------------------------------------------------------------------------------

Next month's profit equation

2x+3y=1593

Rewriting this into slope-equation form

3y = -2x+1593
y=- \frac{2}{3}+ \frac{1593}{3}
y= - \frac{2}{3}+531

The gradient, m, equals to - \frac{2}{3}
The y-intercept, c, equals to 531

The equation still has the same gradient with last month's profit equation but different y-intercept. 

-------------------------------------------------------------------------------------------------------------

A linear graph show points of (0, 300) and (450, 0)

We work out the slope: 
\frac{300-0}{0-450} = \frac{300}{-450}=- \frac{20}{30}  =- \frac{2}{3}


Y-intercept at x = 0, so it's at y = 300

Equation y = - \frac{2}{3}+300

6 0
3 years ago
Suppose that you have he option to buy an item with either cash or credit. Under which condition would you use credit?
Shkiper50 [21]
If they didn't take cash
8 0
2 years ago
Read 2 more answers
Leon has already run 1 mile on his own, and he expects to run 3 miles during each track practice. Write an equation that shows t
maks197457 [2]

Answer:

d = 1 + 3p  

Step-by-step explanation:

Leon already ran 1 miles on his own and he is expected to cover a distance d of 3 miles during each practice. The number of practices is expressed as p and the distance covered is expressed as d.

For every track practice he is expected to cover a distance of 3 miles. Recall he has already cover 1 mile on his own.

Therefore, the relationship between the practices p and the distance d can be expressed as follows.

number of track practice = p

distance covered = d

The distance covered  d in miles is 1 miles plus the number of track practice p multiply by 3

d = 1 + 3p  

5 0
3 years ago
Helpppp: 5x &gt; 35 <br> Show your work to pleasee
Ilya [14]

Answer: X>7

Step-by-step explanation:

5x>35

Divide both by 5

5x/5=x

35/5=7

3 0
3 years ago
Read 2 more answers
Factorise ab+cb+ad+cd ​
shutvik [7]

Answer:

ab=a×b

cb=c×b

ad=a×d

cd=c×d

4 0
2 years ago
Read 2 more answers
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