Is the product of two integers positive, negative, or zero?

1 answer:

6 0

If they both have the same signal than its positive if not its negative. I don't what you mean by zero though i'm in 6th grade

You might be interested in

A function goes through the point (-5,2). What point is the inverse of this function guaranteed to go through ?

adell [148]

the inverse function just changes the coordinates

if f goes through (a,b), then f^-1 must goes through (b,a)

6 0

3 years ago

Charlie is flying a kite one afternoon and steps on the end of the string to have his

Butoxors [25]

Answer:

roubd it to 20 and you will get 679.90

7 0

3 years ago

PLZ HELP ME W DIS!!!

viktelen [127]

Answer:

6^8

Step-by-step explanation:

When the equation looks like this, you can multiply the exponents to give you 6^8. I think that's the kind of answer you're looking for :)

Hope this helps you!

4 0

3 years ago

Please help.<br> Is algebra.<br> PLEASE HELP NO LINKS OR FILES.<br> I don't want links.

Andru [333]

Answer:

Step-by-step explanation:

first, group the terms with the same power together and it would become (-9n⁵-4n⁵)+(n³-9n³)+(11n+6n). then, combine the terms in each group together which would get -13n⁵-8n³+17n as the answer

6 0

3 years ago

Prove : (sec θ - tan θ )^2 = 1 - sin θ /1+sin θ

labwork [276]

$(sec x - tan x)^2 \\ \\ = sec^2x - 2 sec x tan x + tan^2 x \\ \\ =(1+tan^2 x) - 2 sec x tan x +tan^2 x \\ \\ =1 - 2 sec x tan x + 2 tan^2 x \\ \\ = 1 - 2tan x(sec x - tan x) \\ \\ =1 - \frac{2 sin x}{cos x} (\frac{1-sin x}{cos x}) \\ \\ = 1 - \frac{2 sin x (1-sin x)}{cos^2 x} \\ \\ =1 - \frac{2 sin x (1-sin x)}{1-sin^2 x} \\ \\ =1 - \frac{2 sin x (1-sin x)}{(1-sin x)(1+sin x)} \\ \\ =1-\frac{2 sin x}{1+sin x}$

3 0

3 years ago