Question

Which postulate or theorem can be used to prove that △BCD is similar to △EFG?

Answer 1

Answer:

SSS similarity Theorem is correct.

B is correct.

Step-by-step explanation:

Given: We are given two triangle whose measure the side of triangle.

We need to choose correct postulate or theorem.

From the attachment we can see the sides of both triangle.

We will find the ratio of triangle their corresponding side.

$\dfrac{BC}{EF}=\dfrac{28}{14}=\dfrac{2}{1}$

$\dfrac{CD}{FG}=\dfrac{32}{16}=\dfrac{2}{1}$

$\dfrac{BD}{EG}=\dfrac{36}{18}=\dfrac{2}{1}$

In ΔBCD and ΔEFG

$\dfrac{BC}{EF}=\dfrac{CD}{FG}=\dfrac{BD}{EG}=\dfrac{2}{1}$

ΔBCD ≈ ΔEFG  By SSS similarity Theorem

Because three sides are in same ration.

Hence, SSS similarity Theorem is correct.

Answer 2

SSS

since both have all sides known