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Tresset [83]
3 years ago
15

Math is a difficult subject for many students. Often, algebra is the worse, with “what do you mean solve for X? What is X”?! Mat

h basics are in many daily tasks, such as money, time, weight, and distance. What is the one challenging math topic for you (i.e. fractions, division, etc.)? Identify an Internet site for your math topic. It can be a learning site, a video, anything that helps teach the challenged topic. Review the site and provide a brief description, why you like it, and would you recommend it to other students. Check out the other student’s topics and sites.
Mathematics
1 answer:
irakobra [83]3 years ago
3 0
You could just go to kahn academy tho
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What are the first 300 digits of pie first answer is brainiest
Gelneren [198K]

Answer:

3.

141592653589793238462643383279502884197169399375105

82097494459230781640628620899862803482534211706798

21480865132823066470938446095505822317253594081284

81117450284102701938521105559644622948954930381964

42881097566593344612847564823378678316527120190914

5648566923460348610454326648213393607260249141273

Step-by-step explanation:

:)

6 0
3 years ago
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The radius of the bull’s-eye of the dartboard is 8 inches. The radius of each concentric circle is 8 inches more than the radius
UNO [17]

Answer with Step-by-step explanation:

The radius of the bull’s-eye of the dartboard is 8 inches.

The radius of each concentric circle is 8 inches more than the radius of the circle inside it.

Radius of first circle=8 in.

Radius of second circle=16 in.

Radius of third circle=24 in.

Radius of fourth circle=32 in.

Area of C=Area of the third circle-Area of second circle

                     = π×24×24-π×16×16

                   = 320π sq. in.

Total area of dartboard=Area of fourth circle=π×32×32

                                                            =1024π sq. in.

P( the dart will hit in area C)= area of c/total area of dart board

                                             =320π/1024π

                                           =  5/16

Hence, correct option is:

B.5/16

5 0
3 years ago
A landscaper wants to create a 12-foot-long diagonal path through a rectangular garden. The width of the garden is x feet and th
dolphi86 [110]

Answer:

Width of the rectangle =  6.7 ft

length of the rectangle = 10.7 ft

Step-by-step explanation:

ABCD is the rectangle.

AB = length of the rectangle = 4 + x ft

BC = width of the rectangle = x ft

AC = Diagonal of the rectangular field = 12 ft

Since ΔABC is the Right angle triangle. So

AC^{2} = AB^{2} + BC^{2}

12^{2} = (4 + x)^{2} + x^{2}

144 = x^{2} + 16 + x^{2} + 8 x

144 = 2x^{2} + 8x + 16

x^{2} + 4x -72 = 0

By solving above equation we get

x = 6.7 ft

Thus is the width of the rectangle.

And length of the rectangle = 4 + x

⇒ 4 + 6.7

⇒ 10.7 ft

5 0
3 years ago
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Please help!<br> Thank you!
Lena [83]
103. Does not represent a function and 104. Does represent a funtion
4 0
3 years ago
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The mean temperature for the first 7 days in January was 3 °C.
irina1246 [14]

Answer:

Go and ask Google okay you say me like this.

4 0
3 years ago
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