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3 years ago

I need help with this problem! I Don't know how to solve this problem! Please help me.

Mathematics

2 answers:

eduard3 years ago

6 0

You would do:
2x^2 = 16^2
X^2 = 128
X = 8 root2

Aloiza [94]3 years ago

5 0

So.. notice the ratios there,
those ratios are good, when the triangle is
made up of, two 45 degree angles,
and one 90
thus is called a 45-45-90 angle

the two legs are the same length
and the hypotenuse, or longest leg,
whatever the others are, times square root
of 2

so.. one could say that $\bf 16=x\sqrt{2}\implies \cfrac{16}{\sqrt{2}}=x
\\ \quad \\
\textit{now, we could rationalize that by}
\\ \quad \\
\cfrac{16}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}=x\implies \cfrac{16\sqrt{2}}{(\sqrt{2})^2}=x\implies \cfrac{16\sqrt{2}}{2}=x\implies 8\sqrt{2}=x$

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I need help! would appreciate it

dybincka [34]

Answer:

5.407

Step-by-step explanation:

u just use pythag theorem and determine the angle

6 0

3 years ago

Two vectors, X and Y form a right angle. Vector X is 48 inches long and vector Y is 14 inches long. The length of the resultant

krok68 [10]

First Photo - This is the problem drawn into the paper. If you have two vectors and they form a right angle (90°) between them, the Resultant Vector will appear like this, from the right angle.

Obs.:
1 - VR = Resultant Vector;
2 - The angle formed by the VR and the two vectors ISN'T a bisector.

Second Photo - You can move the bottom extremity of the Y vector to the arrow of the X vector and the tips from the Y and VR vectors will meet, forming a Right Triangle, whose the VR is the Hypotenuse (Opposes the right angle / Larger Side).

Now you just put the values in the Pythagorean Theorem:
${a}^{2} = {b}^{2} + {c}^{2}$
Where VR is the "a".

${vr}^{2} = {x}^{2} + {y}^{2} \\ {vr}^{2} = {48}^{2} + {14}^{2} \\ {vr}^{2} = 2304 + 196 \\ {vr}^{2} = 2500 \\ vr = \sqrt{2500} \\ vr = 50 \: inches$

8 0

4 years ago

What is the equation of the line in slope-intercept form that passes through point (4, 5) and is parallel to the line y = −2x −

Anestetic [448]

Answer:

$y=-2x+13$

Step-by-step explanation:

Slope-intercept form of a linear equation:

$y=mx+b$

where:

m is the slope
b is the y-intercept

Given equation:

$y=-2x-2$

Therefore, comparing the given equation with the slope-intercept form:

slope (m) = -2
y-intercept (b) = -2

The slopes of parallel lines are equal.

Therefore, the slope of the new line is -2.

Substitute the given point (4, 5) and the slope m = -2 into the slope-intercept formula and solve for b:

$\implies y=mx+b$

$\implies 5=-2(4)+b$

$\implies 5=-8+b$

$\implies b=13$

Finally, substitute the found values of m and b into the formula to create the equation of the line that passes through the given point and is parallel to the given line:

$\implies y=-2x+13$