The 1st set has 5 different values of +y+
for +x+=+1+ and violates definition
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The 2nd set is a function
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The 3rd set has
( 1,2 ) & ( 1,1 )
( 2,3 ) & ( 2,2 )
( 3,4 ) & ( 3,3 )
Each of these pairs violates the definition
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The 4th set has ( 2,-7 ) & ( 2,0 ) which
violate definition
Answer:
See below
Step-by-step explanation:
When you roll an 8-sided die twice, the sample space is the set of all possible pairs (x,y) where x is the first outcome and y is the second outcome.
The sample space is:
![[(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),(1, 7),(1, 8)\\(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),(2, 7),(2, 8)\\(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),(3, 7),(3, 8)\\(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),(4, 7),(4, 8)\\(5, 1), (5, 2), (5, 3), (5, 4), (5, 5),(5, 6),(5, 7),(5, 8)\\(6, 1), (6, 2), (6, 3), (6, 4)(6, 5),(6, 6),(6, 7),(6, 8)\\(7, 1), (7, 2), (7, 3), (7, 4)(7, 5),(7, 6),(7, 7),(7, 8)\\(8, 1), (8, 2), (8, 3), (8, 4)(8, 5),(8, 6),(8, 7),(8, 8)]](https://tex.z-dn.net/?f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
The sample space of the product xy of each outcome forms the required possibility diagram.
This is given as:
Answer:
x = - 1
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
PLEASE MARK BRAINLIEST!!
Step-by-step explanation:
What exactly are you looking for?
<h3><u>
Answer:</u></h3><h3><u>
752 & 617</u></h3><h3 /><h3><u>
Explanation:</u></h3><h3><u>
So if Liz pays $35 each month just to use the phone, we could subtract 35 from the total bill that month to get the the total cost she spent on text messages.</u></h3><h3 /><h3><u>
March:$72.60-$35=$37.60</u></h3><h3><u>
April: $65.85-$35=$30.85</u></h3><h3 /><h3><u>
We can see that in March Liz spent $37.60 on texts in total and in April she spent $30.85 on texts in total. All we have to do is divide the amount of money she spent on texts( $37.60 & $30.85) by the cost of one text message($0.05) to get the amount of texts she sent that month.</u></h3><h3 /><h3><u>
March: $37.60/$0.05=752</u></h3><h3><u>
April: $30.85/$0.05=617</u></h3><h3 /><h3><u>
Therefore, she sent 752 texts in March and 617 texts in April.</u></h3><h3 /><h3><u>
~FrxziteTheLxoser~ I hoped I help you :)</u></h3>
<u>If i helped you please give me brainIIlest!</u>
