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Natali [406]
3 years ago
13

Evaluate the following. (iii) sin 30° + tan 40° - cosec 60° / cot 45° + cos 60° - sec 30°​

Mathematics
1 answer:
bearhunter [10]3 years ago
4 0

Sin 30 = 1/2

tan 45 = 1

Cosec 60 = 2 / √3 = 2√3 / 3

cot 45 = 1

Cos 60 = 1/2

sec 30 = 2 / √3 = 2√3 / 3

_______________________________

[ 1/2 + 1 - 2√3/3 ] ÷ [ 1 + 1/2 - 2√3/3 ] = <em>1</em>

The face and denominator of the fraction are exactly the same thus the answer is 1 .

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Complete the equation so it has one solution of x=2<br><br> 4(5x-4)=4x___
astraxan [27]

4x____ = 6 so that both sides equal 24

5 0
3 years ago
It took my question down twice here's a real math question I guess
aliina [53]

Answer:

n-3

Interval notation: (-\infty, -10)\cup(-3,\infty)

Step-by-step explanation:

<u>First inequality:</u>

<u />n+8

Therefore, this inequality restricts:

n \in \mathrm{R};\: n

<u>Second inequality:</u>

< 8+n-3

Therefore, this inequality restricts:

n \in \mathrm{R};\: n>-3

Therefore, with both of these restrictions together, we have:

\fbox{$n \in \mathrm{R}; n-3$}\\\mathrm{or\:}\fbox{$n-3$}\\\mathrm{or\:}\fbox{$(-\infty, -10)\cup(-3,\infty)$}.

4 0
3 years ago
Which expression is equivilent to 6(3x-4)+2x
motikmotik

Answer:

44x,

Step-by-step explanation:

you can expand the brackets which equals 18x + 24 (or subtract 24 if the expression is 6(3x-4)) at the end of the equation you will add 2 which would give you 44x

4 0
2 years ago
How does the graph of g(x)= 2^x+3differ from the graph of f(x) = 2^xАIt is moved up 3 unitsBIt is moved down 3 unitsCIt is moved
Readme [11.4K]
\begin{gathered} g(x)=2^{x+3} \\ f(x)=2^x \end{gathered}

4 0
2 years ago
triangle AMY ~ MEG , AM = 5 MY=7 AY =3. MEG IS A DILATION of AMY by a scale facyor of 1/3. fimd the perimeter of MEG.
Mademuasel [1]

Answer:

7

Explanation:

From the question, we're told that triangles AMY and MEG are similar. If triangle AMY has sides AM = 5, MY = 7, and AY = 3 then we can find the side lengths of triangle MEG since we're told from the question that it is a dilation of AMY by a scale factor of 1/3.

So all we need to is multiply the corresponding sides of AMY by 1/3, so we'll have;

\begin{gathered} ME=5\ast\frac{1}{3}=\frac{5}{3} \\ EG=7\ast\frac{1}{3}=\frac{7}{3} \\ MG=3\ast\frac{1}{3}=3 \end{gathered}

We can then go ahead and find the perimeter of MEG. Note that to find the perimeter of a triangle, we add all the length of its sides;

\begin{gathered} \text{Perimeter of MEG}=\frac{5}{3}+\frac{7}{3}+3 \\ =\frac{5+7+9}{3} \\ =\frac{21}{3} \\ =7 \end{gathered}

The perimeter of MEG is 7.

6 0
1 year ago
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