of octane had been converted to carbon dioxide CO₂.
<h3>Explanation</h3>
Octane has a molar mass of

1.000 gallon of this fuel would have a mass of 2.650 kilograms or
, which corresponds to
of octane.
Octane undergoes complete combustion to produce carbon dioxide and water by the following equation:

An incomplete combustion of octane that gives rise to carbon monoxide and water but no carbon dioxide would consume not as much oxygen:

The mass of the product mixture is
heavier than that of the octane supplied. Thus
of oxygen were consumed in the combustion. There are
of oxygen molecules in
of oxygen.
Let the number of moles of octane that had undergone complete combustion as seen in the first equation be
(
). The number of moles of octane that had undergone incomplete combustion through the second equation would thus equal
.
25 moles of oxygen gas is consumed for every two moles of octane that had undergone complete combustion and 17 moles if the combustion is incomplete.


Therefore
out of the 23.2 moles of octane had undergone complete combustion to produce carbon dioxide.

The solvent, solute, and solution.
Answer: 2 C2H4 + 6 O2 => 4 CO2 + 4 H2O
Explanation:The coefficient are as follows: 2: 6: 4: 4
Each atom on the reactant and product side are equal.
Reactant Product
C 2x2 = 4 4x1 = 4
H 2x4 = 8 4x2 = 8
O 6x2 = 12 (4x2) + 4 = 12
Answer:
for the given reaction is -238.7 kJ
Explanation:
The given reaction can be written as summation of three elementary steps such as:



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The substitution product that is supposed to be favoured. The product with retention of configuration is expected to predominate slightly because the leaving group blocks the nucleophile.
<h3>What is a substitution product?</h3>
A substitution product is a product that is gotten from a reaction in which a group of reactants is replaced by another group in the reaction.
Therefore, the substitution product is supposed to be favoured. The product with retention of configuration is expected to predominate slightly because the leaving group blocks the nucleophile.
Learn more about substitution reaction below.
brainly.com/question/10143438
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