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xenn [34]
3 years ago
8

The particles that make up atoms are called _________ particles

Chemistry
1 answer:
belka [17]3 years ago
6 0
D.Subatomic 

  ~~~hope this helps~~~
~~have a beautiful day~~
            ~davatar~
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How many mL 18.0 M H₂SO4 is needed to make 1.50 L of 0.120 M H₂SO4?
lubasha [3.4K]

Answer: You would need 0.67 liters of the concentrated acid. ... To solve for V 1 , multiply 4.0 Molar by 3.00 L and divide by 18.0 M. V1 = M2.V2M1.

Explanation:

8 0
2 years ago
At room temperature, all the metalloids are solids, while most nonmetals are​
Alina [70]

Answer:

at their own state.

That leaves only five elements: carbon, phosphorus, sulfur, selenium, and iodine, which are all non-metals and are solid at room temperature.

4 0
3 years ago
Explain why you hear a “whoosh” sound when you open a can containing a carbonated drink. Which gas law applies?
marishachu [46]

The carbon dioxide in the headspace above the liquid is at higher pressure than atmospheric pressure outside the can.

The gas is at a lower volume initially but suddenly has a larger volume available when the can is opened.

The change in pressure as the gas rapidly moves to become dispersed through its new volume causes the "whoosh" sound.

The gas law that applies is Boyle's law.



This above is the exact answer for edgunity

7 0
3 years ago
Read 2 more answers
Nitric oxide, an important pollutant in air, is formed from the elements nitrogen and oxygen at high temperatures, such as those
Tanya [424]

Answer:

Q is 0.5 and K is 0.01, therefore K is less than Q.

the system will proceed in the reverse direction, thereby converting products into reactants. converting Nitric oxide to form oxygen and nitrogen.

Explanation:

Given,

N2 (g) + O2 (g) « 2 NO (g)

K = 0.01

heated temperature = 2000 ⁰C

N2 moles =0.4

O2 moles =0.1

2NO moles = 0.08

Volume of container = 1L

Q is the reaction quotient  of the equilibrium equation. it is use to determined which direction the system will move to by comparing it with the K value.

Q can be calculated by multiplication of mass of reactant divide by mass of product

Q =\frac{ [N2] *[O2}{2NO}

the mass of the chemicals are in mole, there is need to convert them to moles/litre

therefore,

for N₂ : 0.4 mole per 1L container = 0.4 mol/L = 0.4M

for O₂ : 0.1 mole per 1L container = 0.1 mol/L = 0.1M

for 2NO : 0.08mole per 1L container = 0.08 mol/L = 0.08M

Q =\frac{ [N2] *[O2}{2NO} = (0.4*0.1)/0.08 = 0.5

finally, we are going to compare the value of Q with K

Note that:

if K>Q , the reaction will proceed forward, converting reactants into product.

if K<Q , the reaction will proceed backward, converting products into reactants.

if K=Q , the system of reaction is already in equilibrium.

since, Q is 0.5 and K is 0.01, therefore K is less than Q.

the system will proceed in the reverse direction, thereby converting products into reactants. converting Nitric oxide to form oxygen and nitrogen.

7 0
3 years ago
Calculate the percent ionization of a 0.15 M benzoic acid solution in pure water and in a solution containing 0.10 M sodium benz
Hoochie [10]

Answer:

% ionization for benzoic acid = 0.08%

% ionization for sodium benzoate = 2.5%

The percentage ionization differ significantly because benzoic acid is a weak acid while sodium benzoate is a salt of benzoic acid. Their extent of dissociation also differ because they were compared in different solutions

Explanation:

Ka for pure water = 1.0 * 10-⁷

Ka for sodium benzoate = 6.5*10-⁵

1. For benzoic acid (C6H5COOH)

C6H5COOH ==== C6H5COO‐ + H+

0.15M 0 0

0.15-x x x

Ka = [C6H5COO-] [H+] / [C6H5COOH]

Ka = [X] [X] / 0.15 - X

1.0*10-⁷ = [X]² / 0.15 - x

But x is negligible compared to 0.15,

(1.0*10-⁷)*0.15 = x²

Take square root of both sides,

X = 1.22 * 10-⁴

% ionization = ( [H+] / [C6H5COOH] ) * 100

% ionization = (1.22*10-⁷ / 0.15) * 100

% ionization = 0.08%

2. For C6H5COONa

Note: I will not repeat the same procedure of dissociation again since they're basically the same just the difference in ions

Ka for C6H5COONa = 6.5*10-⁵

6.5*10-⁵ = [X]² / (0.10 - X)

Cross-multiply both sides;

(6.5*10-⁵ * 0.10) = X²

Take square root of both side,

X= 2.5*10-³

% ionization = (2.5*10-³ / 0.10) *100

% ionization = 2.5%

5 0
3 years ago
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